Andre : Anything less than -100, for example -150
-150<-100
|-150|=150
Han: Anything between -100 & 100, for example 50
50> 100
|50|= 50
Lin: 100 or -100,
100> -100
|100|=100
or
-100=-100
|-100|=100
4,200+525(5×12)
4,200+525(60)=
4,200+31,500=35,700
Answer:
The integers are 4 and 7 or -2 and 1.
Step-by-step explanation:
You can make a system of equations with the description of the two integers.
1. x = y + 3
2. 2x + 2 = y^2
The simplest and the fastest way to solve this system in this case is substitution. You can substitute x for y + 3 in the second equation.
1. x = y + 3
2. 2(y + 3) + 2 = y^2
Now simplify and solve the second one. For convenience, I will just disregard the first equation for now.
2y + 6 + 2 = y^2
y^2 - 2y - 8 = 0
You can factor this equation to solve for y.
(y - 4) (y + 2) = 0
y = 4, y = -2
Now we can substitute the value of y for x in the first equation.
x = 7, x = 1
D) 47,000
0.60 (<em>x</em>+38,000)= 51,000
(0.60<em>x</em>)+22,800= 51,000
51,000-22,800= 28,200
28,200÷0.60= 47,000
0.06 (47,000+38,000)= 51,000
28,200+22,800= 51,000
2 is true since the absolute value of -6 is 6 and the absolute value of -8 is 8. The absolute value of a number will always be the number itself but positive. Also 6 is less than five which make this true.
