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vodka [1.7K]
3 years ago
11

If a dozen eggs cost $1.35, what is the unit cost?

Mathematics
1 answer:
Ulleksa [173]3 years ago
4 0
Total eggs=12
dozen eggs cost =1.35 dollars
one egg =12/1.35
=0.11 dollars
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Misha Larkins [42]
27.928cm² the process is shown in the following picture

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2 years ago
In the given figure, find ∠PQS, if∠PQR = 5x + 25 and∠SQR = 2x + 10.
kramer

Answer:

∠PQS= 3(x +5)

Step-by-step explanation:

∠PQR = 5x + 25

∠SQR+∠PQS= 5x+25

∠PQS = ∠PQR-∠SQR

∠PQS= (5x + 25 )-(2x + 10)

∠PQS = 5x+25 -2x-10

∠PQS= 3x +15

∠PQS= 3(x +5)

3 0
3 years ago
Solve the inequality -9 ≤ 7-8v cmon bro
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Answer:

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Step-by-step explanation:

6 0
3 years ago
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
3 years ago
Help me please!<br> What is the median of this data? 48, 60, 22, 84, 36
vova2212 [387]
He is wrong. You first need to put it in order before getting the middle. Like so:
22, 36, 48, 60, 84
Now cross out 22, then 84, and so on till you're left with one number (the middle number)

THE ANSWER IS 48
3 0
3 years ago
Read 2 more answers
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