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GREYUIT [131]
3 years ago
7

How much candy at $1.20 a pound should be mixed with candy worth 95¢ a pound in order to obtain a mixture of 50 pounds of candy

worth a dollar a pound?
Mathematics
1 answer:
Zinaida [17]3 years ago
4 0

Answer:

10 pounds of $1.20 & 40 pounds of $0.95

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What is 6 8/9 times 2 1/2
sammy [17]
SO first off you wanna make both numbers into mix factions. 6 8/9 will be 62/9 and 2 1/2 will be 5/2. Next you wanna multiply straight across. so now the answe should be 310/18 then simply for a mixed number. you can figure that out
5 0
3 years ago
Read 2 more answers
Which inequality doesn't belong?<br> 5/4≤2 8.5≥0.95 8.5≤7 10.00≤100
NNADVOKAT [17]

Answer:

8.5 < 7

Step-by-step explanation:

8.5 is less than 7.

doesn't verify mathematically.

6 0
2 years ago
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Paladinen [302]

Answer:

can u do my delta math? ill do it

Step-by-step explanation:

6 0
3 years ago
Consider a function f(x) such that f(5x) =x-5/5x-1. Find f(x) and hence write down the domain of f(x).
nasty-shy [4]

Answer:

f(x) = \frac{x - 25}{5x - 5}

Domain: x \ne 1

Step-by-step explanation:

Given

f(5x) = \frac{x - 5}{5x - 1}

Required

Determine f(x) and its domain

To determine f(x), we replace 5x with x in f(5x)

So, we have:

f(5x) = \frac{\frac{5x}{5} - 5}{5x - 1}

f(x) = \frac{\frac{x}{5} - 5}{x - 1}

Take LCM

f(x) = \frac{\frac{x - 25}{5}}{x - 1}

f(x) = \frac{x - 25}{5} * \frac{1}{x-1}

f(x) = \frac{x - 25}{5x - 5}

To get the domain, we set the denominator as

5x - 5 \ne 0

5x \ne 5

x \ne 1

4 0
3 years ago
Suppose a manufacturer sells a product as $2 per unit. If q units are sold, (a) write the total revenue function, (b) and find t
Ahat [919]

Answer:

We are given that  a manufacturer sells a product as $2 per unit.

Quantity = q units

So, Total revenue = \text{Cost per unit} \times quantity

Total revenue = 2q

So, the total revenue function is  2q

Marginal revenue is the derivative of the revenue functions

So, Marginal revenue = \frac{dR}{dq} =2

The marginal revenue function is 2

The constant marginal revenue function mean that the revenue earned by the addition of the output is constant.

7 0
3 years ago
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