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Andreyy89
3 years ago
6

A rectangular prism has a length of 20 in., a width of 2 in., and a height of 3 1/4 in. The prism is filled with cubes that have

edge lengths of 1/4 in. How many cubes are needed to fill the rectangular prism? Enter your answer in the box. To fill the rectangular prism, _______ cubes are needed.
Mathematics
2 answers:
goldfiish [28.3K]3 years ago
7 0

Answer: 8320 cubes.

Step-by-step explanation:

1. Calculate the volume of the rectangular prism:

V_1=l*w*h

Where<em> l </em>is the lenght, <em>w</em> is the width and <em>h</em> is the height.

Substitute values.

(You can convert  3 1/4 to decimal by dividing the numerator by the denominator of the fraction and add this to the whole part: 3+0.25=3.25)

Then:

V_1=20in*2in*3.25in=130in^{3}

2. Calculate the volume of a cube:

V_2=s^{3}

Where <em>s</em> is the lenght of any side.

Then:

V_2=(\frac{1}{4}in)^{3}=\frac{1}{64}in^{3}=0.0156in^{3}

3. To calculate the number of cubes that are needed to fill the rectangular prism (which you can call <em>n) </em>, you must divide the volume of the prism by the volume of a cube. Then:

n=\frac{V_1}{V_2}=\frac{130in^{3}}{0.0156in^{3}}=8320 cubes

sergiy2304 [10]3 years ago
6 0

Answer:

8320 cubes. he is right

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\Large\textsc{answer :}

x≤-7

\Large\textsc{calculations :}

First , use the distributive property :

3(x-4)≥5x+2

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Subtract 5x on both sides :

3x-5x-12≥2

Now , add 12 on both sides :

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Divide by -2 on both sides and watch what happens :

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3 years ago
Let <img src="https://tex.z-dn.net/?f=%5Calpha" id="TexFormula1" title="\alpha" alt="\alpha" align="absmiddle" class="latex-form
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Answer:

|\alpha| = 2

Step-by-step explanation:

Since \alpha and \beta are complex conjugates, let's define them as follows:

\alpha = a+bi

\beta = a-bi

\frac{\alpha}{\beta^2}=\frac{a+bi}{a^2-b^2-2abi} =\frac{(a+bi)*(a^2-b^2+2abi)}{(a^2-b^2-2abi)*(a^2-b^2+2abi)} =\frac{a^3-3ab^2+(3a^2b-b^3)i}{a^4+2a^2b^2+b^4}

Since \frac{\alpha}{\beta^2} is a real number, complex part of above result must be zero.

3a^2b-b^3=0

From to hold above equality, b=0 or b^2=3a^2.

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So, b =\sqrt 3 a or b =-\sqrt 3 a

And since \alpha and \beta are complex conjugates, taking plus or minus sign as found above will not affect the result, so let's write the last version of \alpha and \beta as follows:

\alpha = a+\sqrt 3 ai

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Since |\alpha-\beta|=2\sqrt 3

|a+\sqrt 3 ai-a+\sqrt 3 ai|=2\sqrt 3 ⇒ a = 1

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3 years ago
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