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mamaluj [8]
3 years ago
14

Jason cycled for 3 hours. He cycled 7 1/2 miles each hour for the first two hours and the distance he cycled for the third hour

was 1/4 of the total distance he cycled in 3 hours. What was the total distance Jason cycled in 3 hours?
Mathematics
1 answer:
suter [353]3 years ago
3 0

Answer:

Total distance Jason cycled = 20 miles

Step-by-step explanation:

Distance covered in first 2 hours = 2( 7.5)

                                                         =15

Distance covered in the 3rd hour = 15/3                    

                                                                  = 5

Dividing by 3 because the distance covered in the 3rd hour is 1/4 of the distance covered in first two hours. By dividing by 3 we will get 1/4 of the distance

Total Distance =  Distance covered in first two hours

                             + Distance covered in  the 3rd hour                                                                                                                      

                                                                                                       

                             =15  + 5

Total Distance  = 20

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Step-by-step explanation:

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Have a nice day :D

4 0
3 years ago
Whats the gcf of 32 and 52
Molodets [167]
The greatest common factor of 32 and 52 is: 4

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The common factors between them are 1, 2, 4, but the greatest common factor between them is 4.


7 0
3 years ago
Read 2 more answers
compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.
Nina [5.8K]

\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of$\vec{b}$onto $\vec{a}$means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

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Answer:

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7 0
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4 0
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