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2 years ago

PLEASE HELP I've tried over 2 times and failed please help.

Mathematics

1 answer:

Gala2k [10]2 years ago

6 0

Answer:

1. 700 ft. - 800 ft.

2. 85 ft. - 115 ft.

Step-by-step explanation:

Because I'm in highschool

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A 95% confidence interval for an unknown population mean is given by (9, 12). How should this confidence interval be interpreted

Zanzabum

C is my answer of ask other sources tho. Ok

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2 years ago

Rena wrote all the integers from 1 to 12. <br><br> How many numbers did she write?

Aleksandr [31]

Answer:

integers from 1 to 9 have only one number each, so in total 9 numbers. integers from 10 to 12 have 2 numbers each, 3*2=6. 9+6=15

7 0

2 years ago

Read 2 more answers

For a biology project, you measure the weight in grams and the tail length in millimeters of a group of mice. The correlation is

olga nikolaevna [1]

Answer:

Step-by-step explanation:

Given that for a biology project, you measure the weight in grams and the tail length in millimeters of a group of mice.

The correlation is r = 0.9

If you had measured tail length in centimeters instead of millimeters, what would be the correlation?

For this we must understand the meaning of correlation and formula

Correlation is a measure of linear association between the two variables and always lie between -1 and 1

This is got by dividing covariance of (x,y) by product of std deviation of x and y

So because we changed the units of length correlation coefficient would not change.

It would remain the same as 0.90

8 0

3 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

noname [10]

$L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)$

$L_x=10+10\lambda x=0\implies1+\lambda x=0$

$L_y=10+10\lambda y=0\implies1+\lambda y=0$

$L_z=2+4\lambda z=0\implies1+2\lambda z=0$

$L_\lambda=5x^2+5y^2+2z^2-42=0$

$\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z$

$5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1$

$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

$f\left(2,2,1\right)=42\text{ (a maximum value)}$

$f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}$

3 0

3 years ago

Determine which of the lines are parallel and which of the lines are perpendicular. Select all of the statements that are true.

grandymaker [24]

Answer:

Lines a and b are parallel

Lines a and c are perpendicular

Lines d and c are perpendicular

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

Part 1) Find the slope of Line a

we have the points

(-3,4) and (3,6)

substitute in the formula

$m=\frac{6-4}{3+3}$

$m=\frac{2}{6}$

simplify

$m_a=\frac{1}{3}$

Part 2) Find the slope of Line b

we have the points

(-10,-3) and (-8,3)

substitute in the formula

$m=\frac{3+3}{-8+10}$

$m=\frac{6}{2}$

$m_b=3$

Part 3) Find the slope of Line c

we have the points

(0,5) and (3,-4)

substitute in the formula

$m=\frac{-4-5}{3-0}$

$m=\frac{-9}{3}$

$m_c=-3$

Part 4) Find the slope of Line d

we have the points

(4,-7) and (13,-4)

substitute in the formula

$m=\frac{-4+7}{13-4}$

$m=\frac{3}{9}$

simplify

$m_d=\frac{1}{3}$

Part 5) Compare the slopes

Remember that

If two lines are parallel then their slopes are the same

If two lines are perpendicular then their slopes are opposite reciprocal

we have

$m_a=\frac{1}{3}$

$m_b=3$

$m_c=-3$

$m_d=\frac{1}{3}$

therefore

Lines a and b are parallel (slopes are equal)

Lines a and c are perpendicular (slopes are opposite reciprocal)

Lines d and c are perpendicular (slopes are opposite reciprocal)

6 0

3 years ago