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Nana76 [90]
3 years ago
12

Sara claims that the number of pages she has read in her book is proportional to the number of minutes that she has spent readin

g. She collects several data points to prove her claim and expresses the data points as ( x, y) coordinate pairs. Which of the following actions could Sara take to prove her claim? Select two that apply.
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
8 0

Answer:

Here's the answer I got for this problem!  Hope it helps! :)

Step-by-step explanation:

x = 77.789

y = 23

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3. A submarine dives at an
Vesna [10]

Answer:

The height of deepness of submarine is 424.1 feet  

Step-by-step explanation:

Given as :

The angle at which submarine drives of the surface of water = Ф = 13°

The speed at which submarine travel = s = 760 feet per minute

Let The height of deepness of submarine = h feet

The time taken to reach that deepness = t = 5 minutes

<u>According to question</u>

The height of deepness of submarine = \dfrac{\textrm speed}{\textrm time}

i.e h × cos(90 - Ф) = \dfrac{s}{t}

Or,  h × Sin(Ф) = \dfrac{\textrm 760 feet per min}{8 min}

Or,  h × Sin(13°) = 95 feet

Or,   h × 0.224 = 95 feet

∴  h = \dfrac{95}{0.224}

i.e h = 424.10 feet

So, The height of deepness of submarine = h = 424.10 feet

Hence, The height of deepness of submarine is 424.1 feet  Answer

8 0
3 years ago
Find the length of the curve given by ~r(t) = 1 2 cos(t 2 )~i + 1 2 sin(t 2 ) ~j + 2 5 t 5/2 ~k between t = 0 and t = 1. Simplif
xxMikexx [17]

Answer:

The length of the curve is

L ≈ 0.59501

Step-by-step explanation:

The length of a curve on an interval a ≤ t ≤ b is given as

L = Integral from a to b of √[(x')² + (y' )² + (z')²]

Where x' = dx/dt

y' = dy/dt

z' = dz/dt

Given the function r(t) = (1/2)cos(t²)i + (1/2)sin(t²)j + (2/5)t^(5/2)

We can write

x = (1/2)cos(t²)

y = (1/2)sin(t²)

z = (2/5)t^(5/2)

x' = -tsin(t²)

y' = tcos(t²)

z' = t^(3/2)

(x')² + (y')² + (z')² = [-tsin(t²)]² + [tcos(t²)]² + [t^(3/2)]²

= t²(-sin²(t²) + cos²(t²) + 1 )

................................................

But cos²(t²) + sin²(t²) = 1

=> cos²(t²) = 1 - sin²(t²)

................................................

So, we have

(x')² + (y')² + (z')² = t²[2cos²(t²)]

√[(x')² + (y')² + (z')²] = √[2t²cos²(t²)]

= (√2)tcos(t²)

Now,

L = integral of (√2)tcos(t²) from 0 to 1

= (1/√2)sin(t²) from 0 to 1

= (1/√2)[sin(1) - sin(0)]

= (1/√2)sin(1)

≈ 0.59501

8 0
3 years ago
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