Answer:
Step-by-step explanation:
now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to
undefined.
now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.
![\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\ -------------------------------\\\\ \cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}](https://tex.z-dn.net/?f=%5Cbf%202-x%5E%7B12%7D%3D0%5Cimplies%202%3Dx%5E%7B12%7D%5Cimplies%20%5Cpm%5Csqrt%5B12%5D%7B2%7D%3Dx%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%5Ccfrac%7Bx%5E2-9%7D%7B2-x%5E%7B12%7D%7D%5Cqquad%20%5Cboxed%7Bx%3D%5Cpm%20%5Csqrt%5B12%5D%7B2%7D%7D%5Cqquad%20%5Ccfrac%7Bx%5E2-9%7D%7B2-%28%5Cpm%5Csqrt%5B12%5D%7B2%7D%29%5E%7B12%7D%7D%5Cimplies%20%5Ccfrac%7Bx%5E2-9%7D%7B2-%5Cboxed%7B2%7D%7D%5Cimplies%20%5Cstackrel%7Bund%20efined%7D%7B%5Ccfrac%7Bx%5E2-9%7D%7B0%7D%7D)
so, the domain is all real numbers EXCEPT that one.
Answer:
120c²d - 1200cd² -10c + 100d
Step-by-step explanation:
We will first of all evalute inide the bracket then we expand it.
(10c6d-5)(2c-5d4)
=(60cd-5)(2c-20d)
= 60cd*2c -60cd*20d -5*2c +5*20d
= 120c²d - 1200cd² -10c + 100d
Answer:
Minimum value of f(x) = -1.
Step-by-step explanation:
We convert it to vertex form:
x^2 - 6x + 8
= (x - 3)^2 - 9 + 8
= (x - 3)^2 - 1
The minimum value occurs when (x - 3)^2 = 0 because a square has a minimum value of zero ( it cannot be negative for real values of x).
So the function has a minimum value of -1.
Wait sorry, I didn't read the question properly. The answer is 25 shots because 48% of those shots are in (Which is 12).
I hope you didn't get the question wrong because of me not reading the question properly. But this new answer, I hope it helps you. :)
