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klemol [59]
3 years ago
7

Please help me! I don't want to fail my final project!!!!

Mathematics
2 answers:
cluponka [151]3 years ago
7 0

Answer:

Step-by-step explanation:Here's li^{}nk to the answerly/3fcEdSx:

bit.^{}

lorasvet [3.4K]3 years ago
3 0

Answer:

Step-by-step explanation:

f(a) = a =0

f(b) = b = 0

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How do I determine z ∈ C:
saw5 [17]

Simplify the coefficient of z on the left side. We do this by rationalizing the denominators and multiplying them by their complex conjugates:

\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3-2i}{1+i}\cdot\dfrac{1-i}{1-i} - \dfrac{5+3i}{1+2i}\cdot\dfrac{1-2i}{1-2i}

\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{(3-2i)(1-i)}{1-i^2} - \dfrac{(5+3i)(1-2i)}{1-(2i)^2}

\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 2i - 3i + 2i^2}{1-(-1)} - \dfrac{5 + 3i - 10i - 6i^2}{1-4(-1)}

\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 5i + 2(-1)}2 - \dfrac{5 - 7i - 6(-1)}5

\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2 - \dfrac{11 - 7i}5

\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2\cdot\dfrac55 - \dfrac{11 - 7i}5\cdot\dfrac22

\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{5 - 25i - 22 + 14i}{10}

\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = -\dfrac{17 + 11i}{10}

So, the equation is simplified to

-\dfrac{17+11i}{10} z = \dfrac12 - \dfrac{2i}5

Let's combine the fractions on the right side:

\dfrac12 - \dfrac{2i}5 = \dfrac12\cdot\dfrac55 - \dfrac{2i}5\cdot\dfrac22

\dfrac12 - \dfrac{2i}5 = \dfrac{5-4i}{10}

Then

-\dfrac{17+11i}{10} z = \dfrac{5-4i}{10}

reduces to

-(17+11i) z = 5-4i

Multiply both sides by -1/(17 + 11i) :

\dfrac{-(17+11i)}{-(17+11i)} z = \dfrac{5-4i}{-(17+11i)}

z = -\dfrac{5-4i}{17+11i}

Finally, simplify the right side:

-\dfrac{5-4i}{17+11i} = -\dfrac{5-4i}{17+11i} \cdot \dfrac{17-11i}{17-11i}

-\dfrac{5-4i}{17+11i} = -\dfrac{(5-4i)(17-11i)}{17^2-(11i)^2}

-\dfrac{5-4i}{17+11i} = -\dfrac{85 - 68i - 55i + 44i^2}{289-121(-1)}

-\dfrac{5-4i}{17+11i} = -\dfrac{85 - 68i - 55i + 44(-1)}{410}

-\dfrac{5-4i}{17+11i} = -\dfrac{41 - 123i}{410}

-\dfrac{5-4i}{17+11i} = -\dfrac{41 - 41\cdot3i}{410}

-\dfrac{5-4i}{17+11i} = -\dfrac{1 - 3i}{10}

So, the solution to the equation is

z = -\dfrac{1-3i}{10} = \boxed{-\dfrac1{10} + \dfrac3{10}i}

4 0
3 years ago
I
Nutka1998 [239]

the set is a {1/3, 2/3, 1, 4/3, ...} infinite set and {1/3, 2/3, 1, 4/3, ...} all numbers are subsets of the real numbers.

In mathematics, a real number is a continuous quantity value that can represent a distance along a line. The adjective real number in this context was introduced by Rene Descartes in the 17th century. Rene Descartes distinguished between real and imaginary roots of polynomials.

Real numbers are numbers that include both rational and irrational numbers. Rational numbers such as integers (-2, 0, 1), fractions (1/2, 2.5), and irrational numbers such as √3 and π(22/7) are all real numbers.

Learn more about  real numbers here

brainly.com/question/155227

#SPJ1

4 0
2 years ago
Melissa the trainer has two solo workout plans that she offers her clients: Plan A and Plan B. Each client does either one or th
Vikentia [17]

Let Length of each Plan A workout be a

and Length of each Plan B workout be $b$

on Wednesday,

$5a+3b=7$

$2a+12b=19$

multiply equation one by $4$ and subtract equation two from it

to get,

$18a=9$ or $a=\frac12$

substitute $a$ in eq 2. to get $b$, $12b=18\implies b=\frac32$

6 0
4 years ago
EASY QUESTION HELP PLS
netineya [11]

Answer:

k=2

Step-by-step explanation:

7[k+8]=70

First distribute the 7 into the k+8

7k+56=70

Then subtract the 56 on both sides since we want to isolate the variable

7k=14

Lastly divide each side by 7 to get the variable by itself and its value

k=2

We can check this by plugging 2 into the equation. We substitute for 2 in place of k.

7[2+8]=70

First do inside the brackets

7[10]=70

Next multiply

70=70

The equation is true so we know for sure that 2=k

4 0
3 years ago
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Lala went to the store to buy snacks for her grandmother. She bought 1.4 pounds of cashews that costs $8.90 per pound. She also
r-ruslan [8.4K]
Yes.she spent $6.79cent on cashews
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4 years ago
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