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Natasha_Volkova [10]
3 years ago
10

Help on these problems please for my test ​

Mathematics
1 answer:
kvv77 [185]3 years ago
5 0

Answer:

120

Step-by-step explanation:

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-10=-10+ 7m<br>What is the answer?​
Mama L [17]

m = 0............................

5 0
3 years ago
State that dgree of the term -6x²y​
vladimir2022 [97]
I think it’s -6 but I would check with someone else too lol
3 0
3 years ago
Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)
BigorU [14]
For a moment, let y=x^2-2x+5. Then by the distributive property,

(2x^2+4x-3)p=2x^2p+4xp-3p


Again by the distributive property,

2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2

4xp=4x(x^2-2x+5)=4x^3-8x^2+20x

-3p=-3(x^2-2x+5)=-3x^2+6x-15

Taking everything together, we get

(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)
(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15
7 0
3 years ago
Read 2 more answers
Pls help me with this no links please and Thank you
den301095 [7]
The top graph is correct because an x=# will create a vertical line at that #
4 0
3 years ago
Read 2 more answers
For which of the following compound inequalities is there no solution? ​
Bess [88]

Answer:

(a)6m \le - 36 and m + 24 > 20

Step-by-step explanation:

Required

Which of a to d has no solution

(a)6m \le - 36 and m + 24 > 20

We have: m + 24 > 20

Sole for m

m >20 - 24

m >-4

6m \le - 36

Divide by 6

m \le -6

So, we have:

m \le -6 and m >-4

m \le -6 implies that: m = -6,-7,-8,-9.....

m >-4 implies that m = -3,-2,-1,0.....

<em>Hence, there is no solution</em>

8 0
3 years ago
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