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Allisa [31]
3 years ago
8

For Sunday brunch, Kayli is making a recipe that requires 8 cups of milk. She has 3 quarts of milk. Does she have enough for the

recipe? Explain your answer using numbers and words.
Mathematics
1 answer:
Dovator [93]3 years ago
3 0

Answer:

yes she has more than enough

Step-by-step explanation:

1 quart = 4 cups

2 quarts = 8 cups

3 quarts = 12 cups

You might be interested in
Solve: x+2/x-4&lt;0<br> O _4 O -2 -2 -4
sammy [17]

Answer:

-2<x<4

Step-by-step explanation:

For \frac{x+2}{x-4} < 0, note that either the numerator or denominator is positive and the other must be negative for this inequality to be satisfied.

This means x+2>0 and x-4<0 or x+2<0 and x-4>0.

Lets look at the first scenario (x+2>0 and x-4<0)

x+2>0 and x-4<0

x>-2 and x<4

This means that -2<x<4.

Let’s look at the other scenario (x+2<0 and x-4>0)

x+2<0 and x-4>0

x<-2 and x>4

This means that x must be <-2 and >4 simualtaneously, which is impossible.

Therefore, this only occurs when -2<x<4.

I hope this helps! :)

7 0
3 years ago
The difference of eight and twice a number
Over [174]

Answer:

8 - 2x

Step-by-step explanation:

Let x be the unknown number

difference is subtraction

8 - 2x

4 0
3 years ago
Which is a pair of vertical angles?
xz_007 [3.2K]

Answer:

< TRS and <VRW

Step-by-step explanation:

3 0
3 years ago
Help me thank you <br> .......
katrin2010 [14]

Answer:

$2.71

Step-by-step explanation:

$2 dollars in ones + $0.50 in quarters + $0.20 in dimes + $0.01 in pennies equals out to $2.71

8 0
3 years ago
Five cards are dealt from a standard 52-card deck. (a) What is the probability that we draw 1 ace, 1 two, 1 three, 1 four, and 1
labwork [276]

Answer:

Step-by-step explanation:

As there are total 52 cards in a deck and we have to draw a set of 5 cards, we can use the formula of combination to find the total number of possible ways of drawing 5 cards.

Number of ways to draw 5 cards = N_T

N_T\;=\;({}^NC_k)\\\\N_T\;=\;({}^{52}C_5)\\\\N_T\;=\;2,598,960

(a) Assuming the cards are drawn in order (would not affect the probability). The of getting Ace, 2, 3, 4 and 5 can be obtained by multiplying the probability of getting cards below 6 (20/52) with the probability of getting 5 different cards (4 choices for each card).

P(a)\;=\;\frac{20}{52}*\frac{4}{52}*\frac{4}{51}*\frac{4}{50}*\frac{4}{49}*\frac{4}{48}\\\\P(a)\;=\; 1.3133*10^{-6}

(b) For a straight we require our set to be in a sequence. The choices for lowest value card to produce a sequence are ace, 2, 3, 4, 5, 6, 7, 8, 9, or 10. Hence, the number of ways are ({}^{10}C_1).

For each card we can draw from any of the 4 sets. It can be described mathematically as: ({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)\;=\;[({}^{4}C_1)^5]

Therefore, the total outcomes for drawing straight are:

N_S\;=\;({}^{4}C_1)*({}^{4}C_1)^5\;=\;10240

Thus, the probability of getting a straight hand is:

P(b)\;=\;\frac{N_S}{N_T}\\\\P(b)\;=\;\frac{10240}{2598960}\\\\P(b)\;=\; 0.0039

7 0
3 years ago
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