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vesna_86 [32]
3 years ago
14

To replace the trees destroyed by typhoon Yolanda, the forestry department of Tagaytay has developed a ten-year plan. During the

first year they will plant 100 trees. Each succeeding year, they will plant 50 more trees than they planted the year before.
Mathematics
1 answer:
AveGali [126]3 years ago
5 0

Answer:

a. 1,000 trees

b. 3,250 trees

Step-by-step explanation:

a. How many trees will they plant during the fifth year?

b. How many trees will they have planted by the end of the tenth year?​

Using the sum of an arithmetic progression formula

Sn = n/2 {2a+(n-1)d}

Where,

Sn = Sum of an n terms

n = number of terms

a = first term

d = common difference

a.

n = 5

a = 100

d = 50

S5 = n/2 {2a+(n-1)d}

= 5/2 {2*100 + (5-1)50}

= 5/2 {200+(4)50}

= 5/2{200 + 200}

= 5/2(400)

= 2,000 / 2

= 1,000

S5 = 1,000 trees

b. Sn = n/2 {2a+(n-1)d}

n = 10

a = 100

d =50

S10 = 10/2{2*100 + (10-1)50}

= 5{200 + (9)50}

= 5{200 + 450}

= 5(650)

= 3,250

S10 = 3,250 trees

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The number of adult tickets is the same as the number of child (age5-12)tickets.A total of 38 tickets was purchased. What is the
Nutka1998 [239]

Answer:

$760

Step-by-step explanation:

The number of adult ticket is the same as the number of (age 5-12) tickets.

Let the number of adult ticket be x

Number of (age 5-12) tickets be x

Total ticket sold = 38

x + x = 38

 2x = 38

  x = 19

Cost of each adult ticket = $23

Total cost for 19 such tickets = 23×19

                                               = $437

Cost of each (age 5-12) ticket = $17

Total cost for 19 such tickets = 19×17

                                               = $323

Total cost of 38 tickets = 437 + 323

                                       = $760

Hence, the total cost of tickets is $760

Step-by-step explanation:

6 0
3 years ago
Pizza Palace and Saucy Sam’s both offer food delivery. Both have a deal for large pizzas. You have to buy a lot of pizzas for yo
pochemuha

Answer:

Now lets add up how much it would cost for a SINGLE pizza at both pizza places, which I am rounding up to the next dollar for this.

Step-by-step explanation:

Pizza Palace:

5 + 9 = 14

Meaning, if you were to get many pizzas, just a single one delivered costs 14 bucks, but all you have to do to add more pizzas to it is:

5 + 9p = ?, where p is the number of pizzas ordered

Saucy Sam's:

5 + 12 = 17

Meaning, if you were to get many pizzas, a single one delivered costs 17 bucks, but all you have to do to add more pizzas to it is:

5p + 12 = ?, where p is the number of pizzas ordered

BUT, heres where it tricks you, lets take both equations and choose a number that equals P. We can choose........ 10.

5 x 10 + 12 = 62

This means, that 10 pizzas of Saucy Sam's costs 62 dollars

5 + 9 x 10 = 95

This means, that 10 pizzass of Pizza Palace costs 95 dollars.

Saucy Sams has the best price.

7 0
3 years ago
3+ Зу – 1+y ,ASAP please help
Fiesta28 [93]

Answer:

5y

Step-by-step explanation:

Brainliest me pls

Have a nice day!

6 0
3 years ago
There are 87 green balls and 41 red balls in a bag. If one is randomly selected, what is the probability that it will be a green
garri49 [273]

Number of green balls = 87

Number of red balls = 41

So total number of balls = 128

Probability formula = number of events / number of possible outcomes.

So, the probability that a ball randomly selected will be a green ball will be

\frac{87}{87+41}

equals 0.6796875 converting to nearest hundredth as 0.68


5 0
3 years ago
Find the point on the plane ax + by + cz = d at minimum distance from the origin using the method of lagrange multipliers.
kupik [55]
The distance between some point (x,y,z) and the origin is given by

f(x,y,z)=\sqrt{x^2+y^2+z^2}

so this is the function we're trying to minimize. But notice that f(x,y,z) and f(x,y,z)^2 attain their critical points at the same (x,y,z), so we can solve the same problem by minimizing x^2+y^2+z^2 instead.

So let's take the Lagrangian to be

L(x,y,z,\lambda)=x^2+y^2+z^2+\lambda(ax+by+cz-d)

with partial derivatives (set equal to 0)

L_x=2x+a\lambda=0
L_y=2y+b\lambda=0
L_z=2z+c\lambda=0
L_\lambda=ax+by+cz-d=0

Now, notice that

aL_x+bL_y+cL_z=2(ax+by+cz)+(a^2+b^c+c^2)\lambda=0
\implies\lambda=-\dfrac{2d}{a^2+b^2+c^2}

and we can use this to solve for x,y,z. We get

x=\dfrac{ad}{a^2+b^2+c^2}
y=\dfrac{bd}{a^2+b^2+c^2}
z=\dfrac{cd}{a^2+b^2+c^2}

At this critical point, we get a minimum distance of

\sqrt{\left(\dfrac{ad}{a^2+b^2+c^2}\right)^2+\left(\dfrac{bd}{a^2+b^2+c^2}\right)^2+\left(\dfrac{cd}{a^2+b^2+c^2}\right)^2}=\sqrt{\dfrac{d^2}{a^2+b^2+c^2}}
8 0
3 years ago
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