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pashok25 [27]
3 years ago
11

A rectangle has a length of 4 feet and a perimeter of 14 feet. What is the perimeter of a similar rectangle with a width of 9 fe

et? **We are learning about proportions**
A. 36 ft
B. 108 ft
C. 42 ft
D. 126 ft​
Mathematics
1 answer:
mina [271]3 years ago
5 0

Answer:

Option C. 42\ ft

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor and the ratio of its perimeter is equal to the scale factor too

step 1

Find the width of the rectangle that has a length of 4 feet and a perimeter of 14 feet

The perimeter of a rectangle is equal to

P=2(L+W)

substitute the values and solve for W

14=2(4+W)

W=7-4=3\ ft

step 2

Find the scale factor

Let

z-----> the scale factor

To find the scale factor divide the width of the larger rectangle by the width of the smaller rectangle

so

9/3=3

step 3

Find the perimeter of the larger rectangle

To find the perimeter of the larger rectangle multiply the perimeter of the smaller rectangle by the scale factor

so

3*14=42\ ft

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marta [7]
<h3>Answer:</h3>

<em>The theoretical probability to draw a black marble is </em><u><em>0.23</em></u><em>. </em>

Step-by-step explanation:

First add up the total amount of marbles in the bag.

14 gray marbles + 7 black marbles + 10 white marbles = 31 total marbles.

Since we need the odds of a black marble being drawn, divide 7 (the amount of black marbles) by 31 (the amount of total marbles).

7/31 ---> 0.22580645161   <u><em>(it is easiest to use a calculator on this step)</em></u><em> </em>

Lastly, round the decimal to the nearest hundredth.

0.22580645161 ---> <em>0.23</em>

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4 years ago
2. The larger circle of an annulus has a diameter of 10 cm, and the smaller circle has a diameter of 7.6 cm. What is the area of
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Answer:

Area = 3.77 cm^2

Step-by-step explanation:

The diagram using the given statement is attached below

Diameter of larger circle is 10 so radius R1 = 10/2= 5

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We need to find the area of the shaded region

Area of the circle =\pi r^2

Area of annulus =\pi R1-\pi r1

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