Answer:
5.12 molecules of Ag₂S could be produced from 10 molecules of silver.
Explanation:
Given data:
Molecules of Ag = 10 molecules
Molecules of Ag₂S = ?
Solution:
First of all we will convert the number of molecules into gram.
10/ 6.022 ×10²³ = 1.7 × 10⁻²³ mol
Mass of Ag:
Number of moles = mass/ molar mass
Mass = Number of moles × molar mass
Mass = 1.7 × 10⁻²³ mol × 107.9 g/mol
Mass = 183.43 × 10⁻²³ g
Chemical equation:
2Ag + H₂S → Ag₂S + H₂
Now we will compare the moles of silver with Ag₂S from balanced chemical equation.
Ag : Ag₂S
2 : 1
1.7 × 10⁻²³ : 1/2 ×1.7 × 10⁻²³ = 0.85 × 10⁻²³ mol
Molecules of Ag₂S:
0.85 × 10⁻²³ × 6.022 ×10²³ = 5.12 molecules
Answer: HF-dipole- dipole interaction
CH3OH- dipole-dipole interaction
CaCl2- ion-ion interaction
Explanation:
Both CH3OH and HF possess permanent dipoles which interact with water leading to the dissolution of the above named substances. Remember that water also possesses a permanent dipole. Which can interact with the dipoles on other polar molecules. CaCl2 is purely ionic and interacts with water via ion-dipole mechanism.
Answer:
Electrostatic smoke precipitators work by forcing dirty flue gas (the gas escaping from a smokestack) past two electrodes (electrical terminals), which take the form of metal wires, bars, or plates inside a pipe or smokestack
Explanation:
Answer:
its easy ask to chrome or search in yt ;)
Answer:
P₂ = 0.205torr
Explanation:
Boyle's law relates the pressure and volume of a gas under two different conditions. The equation is:
P₁V₁ = P₂V₂
<em>Where P is pressure and V volume of of 1, initial conditions and 2, final conditions.</em>
P₂ is our incognite
Replacing:
P₁V₁ = P₂V₂
8.20x10⁴torr*15.0L = P₂*600x10⁴L
<h3>P₂ = 0.205torr</h3>
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