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svetlana [45]
3 years ago
5

Which gas below has the largest number of moles at STP?

Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
6 0

Answer:

a.) 22.4 L Ne.

Explanation:

It is known that every 1.0 mol of any gas occupies 22.4 L.

For the options:

  • 22.4 L Ne:

<em>It represents </em><em>1.0 mol of Ne.</em>

<em />

  • 20 L Ar:

using cross multiplication:

1.0 mol occupies → 22.4 L.

??? mol occupies → 20 L.

The no. of moles of (20 L) Ar = (1.0 mol)(20 L)/(22.4 L) = 0.8929 mol.

  • 2.24 L Xe:

using cross multiplication:

1.0 mol occupies → 22.4 L.

??? mol occupies → 2.24 L.

<em>The no. of moles of (2.24 L) Xe </em>= (1.0 mol)(2.24 L)/(22.4 L) = <em>0.1 mol.</em>

  • So, the gas that has the largest number of moles at STP is: a.) 22.4 L Ne.

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Answer:

13.4g

Explanation:

we know that:

1 mole = 6.02 × 10²³ atoms

make the unknown number of moles = x

x = 7.1 × 10²² atoms

putting them both together:

1 mole = 6.02 × 10²³ atoms

x = 7.1 × 10²² atoms

Cross multiply:

6.02 × 10²³ x = 7.1 × 10²²

divide both sides by 6.02 × 10²³

x =  \frac{7.1  \times  10²² }{  6.02 × 10²³}

x =  \frac{71}{602}

we now have the number of moles of Al₂CO₃

to calculate the grams (mass):

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