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Vitek1552 [10]
3 years ago
5

Karla is selling tickets for a high school play. Child tickets cost $7 and adult tickets cost $13 she sells 180 tickets and coll

ects $1830 Setup a system of equations using C for number of child tickets and A for number of adult tickets to find the number of each ticket sold
Mathematics
1 answer:
ycow [4]3 years ago
3 0

Answer: The number of child tickets is 85 and the number of adult tickets is 95.

Step-by-step explanation:

Let C = Number of child tickets

A = Number of adult tickets.

As per given, we have

C+A=180          (i)

7C+13A=1830           (ii)

Multiply 7 to both sides of equation (ii), we get

7C+7A=1260     (iii)

Eliminate (iii) from (ii) , we get

6A=570\\\\\Rightarrow\ A=95

Put value of y in (i), we get

C= 85

Hence, the number of child tickets is 85 and the number of adult tickets is 95.

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Answer:

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Step-by-step explanation:

The equation is \log _{3}(x+5)=2

Option a: \log _{3}(x+5)=3^{2}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option a is not equivalent to \log _{3}(x+5)=2

Option b: \log _{3}(x+5)=2^{3}

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Option c: x+5=3^{2}

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Thus, the correct option is c: x+5=3^{2}

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3 years ago
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