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Blababa [14]
2 years ago
10

A magnet that is an iron core wrapped with electrical wire is called a(n):

Mathematics
1 answer:
andriy [413]2 years ago
7 0

electromagnet

hope it helps...!!!

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An item sells for $40 . The sales tax on the item is 8%. What is the sales tax and total cost?
In-s [12.5K]

Answer:

The sales tax is $3.2 and the total cost is $43.2.

Step-by-step explanation:

Multiply 0.08 by $40 to find the sales tax  (8% is the same as 0.08)

Then add 3.2 (sales tax) to the regular price to find the total price.

5 0
3 years ago
The vertical height v, in feet, of a snowboarder jumping off of an overhang can be modeled by the function h(t)=15-10t-16t^2, wh
olga55 [171]
I don't know for sure, but I think there might be an error in the way you copied your function. In all of my dealings with these types of problems, I have learned the formula to be h(t) = 15 + 10t - 16t^2. Notice the plus in front of the "10t". This is due to the fact that if he pushes off of the overhang he would have an upward force of 10 feet per second as soon as his feet left the ground. The only thing pulling him back to Earth is gravity, modeled by the "-16t^2". This is derived from a bit of slightly advanced physics involving the gravitational constant, but let's work under my formula for a second...

Either way, we will wind up using the Quadratic Formula (or possibly factoring if the numbers are easy enough to work with). So let's start. 

h(t)= 15 +10t - 16t^2

In order to use the QF or factoring I will need to make h(t)=0. Simply done by:

0= 15 +10t -16t^2

Looking at the numbers, I'd prefer to use the QF so here it is:

x= \frac{-b + or -  \sqrt{b^{2}-4ac } }{2a}

I know that my answer will need to be positive since you can't have a negative value when dealing with time, so I will eliminate the positive sign from the "+or-" part leaving me with:

x= \frac{-b -\sqrt{b^{2}-4ac } }{2a}

And I know that a= -16, b= 10, and c=15. So all that's left to do is substitute and solve.

x= \frac{-10 -\sqrt{-16^{2}-4*-16*15 } }{2*-16} 

There's a decent amount of math that would be difficult and sloppy for me to do over the computer, but all you need to do is solve the rest of the equation and you would get your answer.

Exact answer: \frac{5-4 \sqrt{15} }{8} or rounded answer: ≈1.31 seconds.

Hope this helps!
NoThisIsPatrick

7 0
3 years ago
Read 2 more answers
A community park is shaped like a trapezoid with a height of 30 yd, a top base of 25yd,and a bottom base of 33yd. The park has a
Likurg_2 [28]

Answer: 819.73 yd²

<u>Step-by-step explanation:</u>

A_{trapezoid} = \frac{b_{1}+b_{2}}{2}*h

                       = \frac{25+33}{2}*30

                       = \frac{58}{2}*30

                       = 29 * 30

                       = 870

A_{circle} = \pi r^{2}

                  = π(4)²

                  = 16π

                  ≈ 50.27

Area of the park = A_{trapezoid} - A_{circle}

 = 870 - 50.27

= 819.73

6 0
3 years ago
an ellipse has a center at the origin , a vertex along the major axis at (13,0), and a focus at (12,0). What is the equation of
-BARSIC- [3]

Answer:

The answer to your question is below

Step-by-step explanation:

Data

Center = (0, 0)

Vertex = (13, 0)

Focus = (12, 0)

Process

From the data we know that it is a horizontal ellipse.

1.- Calculate "a", the distance from the center to the vertex.

                  a = 13

2.- Calculate "c", the distance from the center to the focus

                  c = 12

3.- Calculate b

Use the Pythagorean theorem to find it

                  a² = b² + c²

-Solve for b

                  b² = a² - c²

-Substitution

                  b² = 13² - 12²

-Simplification

                  b² = 169 - 144

                  b² = 25

                  b = 5

4.- Find the equation of the ellipse

                       \frac{x^{2} }{13^{2}} + \frac{y^{2}}{5^{2}} = 1    or \frac{x^{2} }{169} + \frac{y^{2}}{25} = 1

7 0
3 years ago
10 POINTS AND BRAINLIEST<br> Please answer all 3 questions attached correctly.
lana66690 [7]

Answer:

#1. Identity #2. 0 #3. No solution

Step-by-step explanation:

#1.

5y + 2 = (1/2)(10y+4)

5y + 2 = 5y + 2

This would be identity as the equation of the left and right are the same. This is not to be confused with no solution(explained below).

#2.

0.5b + 4 = 2(b+2)

0.5b + 4 = 2b + 4

0.5 b - 2b = 0

b = 0

#3.

-3x + 5 = -3x + 10

This equation has no solution because when you try to bring the -3x to one side, the x variable itself gets eliminated. So, how is it different from identity? Well in the first equation, it is true that when we try to bring the 5y one side it eliminates the y variable, however, that is also true for the constants(since if we try to bring the 2 to one side, it will be 2-2 which will equal 0, thus eliminating each other), but in this case, even if we remove the x, the constants will not equal 0, thus it will have no solution.

5 0
3 years ago
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