If we draw the contingency table of x (vertical) against y (horiz.), we have a square.
For n=4, we have (legend: < : x<y = : x=y > : x>y
y 1 2 3 4
x
1 = < < <
2 > = < <
3 > > = <
4 > > > =
We see that there are n(n-1)/2 cases of x<y out of n^2.
Therefore,
p(x<y)=n(n-1)/(2n^2)=(n-1)/(2n)
However, if the sample space is continuous, it will be simply p(x<y)=1/2.
Answer:
The y intercept should be 2 lower than the original equation
Step-by-step explanation:
The answer is C .12/15 since you can divide A,B,D and get 2/3 but you cannot with C
Reflecting over the y-axis
The square 8 units is above the grid for stage. Coordinations was the location
