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3 years ago

12

What is 49÷34÷45=? Pleeeeeeeessse I need help

2 answers:

fenix001 [56]3 years ago

8 0

Answer:

0.032

Step-by-step explanation:

So we just go in order:

49 ÷ 34 = 1.44 (simplified)

1.44 ÷ 45 = 0.032 (simplified)

So 49 ÷ 34 ÷ 45 = 0.032

hope this helps:)

ra1l [238]3 years ago

4 0

Answer:

The answer is 0.032026144

Step-by-step explanation:

Hoped This helped!

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Pleaseeee helppp !!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!

LuckyWell [14K]

Since triangle STU and TVW are similar angle VWT and SUW are equal, this means:
106-5x=7x-14
(106)+(14)=(7x)+(5x)
120=(12x)
10=(x)
Angle VWT=106-5x=106-(5)(10)=56

6 0

3 years ago

15 crackers weigh 69 grams. how many kilograms is this?

Marrrta [24]

Answer:

$0.069\ kg$

Step-by-step explanation:

we know that

1 kg=1,000 g

so

using proportion

Find out how many kilograms are 69 grams

Let

x -----> the weight in kg

$\frac{1}{1,000}\frac{kg}{g} =\frac{x}{69}\frac{kg}{g}\\\\x=\frac{69}{1,000}\\\\x=0.069\ kg$

6 0

4 years ago

Given the expression: 3x10 − 48x2

BartSMP [9]

Factorization involves representing an expression with smaller terms.

<em>When the greatest common factor is factored out, the equivalent expression is: </em> $3x^2(x^8 - 16)$ <em>.</em>
<em>The complete factored expression is: </em> $3x^2(x^4 - 4)(x^4 + 4)$ <em />

The expression is given as:

$3x^{10} -48x^2$

The GCF of $3x^{10}$ and $48x^2$ is $3x^2$ .

So, we have:

$3x^{10} -48x^2 = 3x^2 \times x^8 - 3x^2 \times 16$

Factor out $3x^2$

$3x^{10} -48x^2 = 3x^2(x^8 - 16)$

To factorize the expression completely, we express $x^8$ and $16$ as squares.

So, we have:

$3x^{10} -48x^2 = 3x^2((x^4)^2 - 4^2)$

Apply difference of two squares

$3x^{10} -48x^2 = 3x^2(x^4 - 4)(x^4 + 4)$

So, the complete factor of $3x^{10} -48x^2$ is $3x^2(x^4 - 4)(x^4 + 4)$

Read more about factorization at:

brainly.com/question/19386208

3 0

2 years ago

HELP ME WIT THIS QUICK

sweet-ann [11.9K]

Answer:

3

Hope this helps Buddy!

- Courtney

5 0

3 years ago

Read 2 more answers

A random sample of 500 registered voters in Phoenix is asked if they favor the use of oxygenated fuels year-round to reduce air

Stells [14]

Answer:

a) 0.0853

b) 0.0000

Step-by-step explanation:

Parameters given stated that;

H₀ : <em>p = </em>0.6

H₁ : <em>p = </em>0.6, this explains the acceptance region as;

p° ≤ $\frac{315}{500}$ =0.63 and the region region as p°>0.63 (where p° is known as the sample proportion)

a).

the probability of type I error if exactly 60% is calculated as :

∝ = P (Reject H₀ | H₀ is true)

= P (p°>0.63 | p=0.6)

where p° is represented as <em>pI</em><em> </em>in the subsequent calculated steps below

= P $[\frac{p°-p}{\sqrt{\frac{p(1-p)}{n}}} >\frac{0.63-p}{\sqrt{\frac{p(1-p)}{n}}} |p=0.6]$

= P $[\frac{p°-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} >\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} ]$

= P $[Z>\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500} } } ]$

= P [Z > 1.37]

= 1 - P [Z ≤ 1.37]

= 1 - Ф (1.37)

= 1 - 0.914657 ( from Cumulative Standard Normal Distribution Table)

≅ 0.0853

b)

The probability of Type II error β is stated as:

β = P (Accept H₀ | H₁ is true)

= P [p° ≤ 0.63 | p = 0.75]

where p° is represented as <em>pI</em><em> </em>in the subsequent calculated steps below

= P $[\frac{p°-p} \sqrt{\frac{p(1-p)}{n} } }\leq \frac{0.63-p}{\sqrt{\frac{p(1-p)}{n} } } | p=0.75]$

= P $[\frac{p°-0.6} \sqrt{\frac{0.75(1-0.75)}{500} } }\leq \frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P $[Z\leq\frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P [Z ≤ -6.20]

= Ф (-6.20)

≅ 0.0000 (from Cumulative Standard Normal Distribution Table).

6 0

3 years ago