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Ad libitum [116K]
3 years ago
6

In the circle below, EG is a diameter and EF is tangent at E. Suppose mEF = 124°. Find the following. Does anyone know this?

Mathematics
1 answer:
Ludmilka [50]3 years ago
8 0

Answer:

Step-by-step explanation:

If EG is a diameter, then arc EFG is a semicircle and its measure is 180. Arc FG then is 180 - 124 = 56. Since angle FEG is an inscribed angle and the arc it cuts off is arc FG, then the measure of the inscribed angle is half the measure of the arc it cuts off...so angle FEG is 28 degrees. Keep that in mind; we'll need it in a sec.

If HE is tangent to the circle at E, then angle HEG is a 90 degree angle. Adding that to angle FEG will give you angle FEH. Angle FEH = 90 + 28 = 118

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4 years ago
a textbook company ships its books in boxes that can hold 30 pounds. one particular order calls for a shipment of 800 books. if
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83 boxes are required to carry 800 books.

According to the question:

One Box can hold weight = 30 pounds

We know that ,  1 pound= 0.45 kg

hence, 30 pounds = 30 x 0.45 = 13.5kg  

hence,  one box can carry 13.5 kg of weight.

Now,

Weight of 1 book = 1.4 kg

So, Total Weight of 800 books= 1.4 x 800 kg

And , No. of boxes required to carry 800 books = (1.4 x 800)/13.5 = 82.96

                                                                             or approximately 83 boxes

Hence, 83 boxes are required to carry 800 books.

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brainly.com/question/19423643

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4 0
2 years ago
Solve the equation on the interval 0 less than or equals theta less than 2 pi 0≤θ<2π. 2 cosine theta plus 1 equals 0 2cosθ+1=
VARVARA [1.3K]

Answer:

θ = 2π/3 or 5π/3

Step-by-step explanation:

2 cosθ + 1= 0

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since cosθ is negative

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it means either cosθ lies in 2nd or third quadrant

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or

θ = 2π- π/3

so θ = 2π/3 or 5π/3

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Answer:

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