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Lapatulllka [165]
2 years ago
10

Find line tangent to y=xcosx at point (pi, -pi)

Mathematics
1 answer:
slamgirl [31]2 years ago
5 0
1) slope of the line = derivative of the of the function at the given point.

y' = cosx - x cosx

Evaluate for x = pi => y' = cos(pi) - pi*cos(pi) = -1 - (pi*cos(pi)) = -1 + pi

Then slope = -1 + pi

Given point: (pi, -pi)

Equation:

y - (-pi) = [-1+ pi] (x - pi)

y + pi = -x +pi + xpi -pi^2

y = (pi-1)x - pi^2      .... this is the answer
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Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

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Where \mu and \sigma=0.08

Since the distribution for X is normal then the  we know that the distribution for the sample mean \bar X is given by:

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