1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inessss [21]
3 years ago
15

Sin40°-sin20°/cos220°-cos200=√3​

Mathematics
1 answer:
Mumz [18]3 years ago
7 0

Answer:

1.7320508

Step-by-step explanation:

You might be interested in
the 41st term of the arithmetic sequence is -539 and the 54th term is -708. Find the value of the 80th term
yulyashka [42]

Answer:

a _{n} = a _{1} + (n - 1)d \\ a _{41} =  - 534 \\ a _{54} =  - 708 \\  a _{41} =  a _{1} + (41 - 1)d = - 534  \\  a _{1} + 40d = - 534 \:  \: ...(1)\\ a _{54} =  a _{1} + (54 - 1)d =- 708 \\ a _{1} + 53d = - 708 \:  \: ...(2)

Try to solve the similtanious equation to find the first term and the common difference, then use that information to figure out the 80th term... Update me if you need further help ...

7 0
3 years ago
What kinetic energy has a 4kg shootput thrown with a velocity of 12m/s
Tamiku [17]

Answer:

288J

Step-by-step explanation:

recall the formula for kinetic energy

KE = (1/2) mv²

where m is the mass (= 4kg)  and v is the velocity(=12 m/s)

hence

KE = (1/2) (4)(12)² = 288J

7 0
3 years ago
Read 2 more answers
What is the equation of a line that passes through the point (9, −3) and is parallel to the line whose equation is 2x−3y=6 ?
vlabodo [156]
2x - 3y = 6
-3y = -2x + 6
y = 2/3x - 2....the slope here is 2/3. A parallel line will have the same slope

y = mx + b
slope(m) = 2/3
(9,-3)...x = 9 and y = -3
now we sub and find b, the y int
-3 = 2/3(9) + b
-3 = 6 + b
-3 - 6 = b
-9 = b

so ur parallel equation is : y = 2/3x - 9 <== or 2x -3y = 27
6 0
3 years ago
Read 2 more answers
Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

__

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
A bean plant grows at a constant rate for a month. After 10 days, the plant is 25 centimeters tall. After 20 days, the plant is
wariber [46]
Y = 2x + 5

If you take the height at 10 days, 25 centimeters, after 10 more days the height is 45 centimeters, meaning for those 10 extra days the been plant grown 20 centimeters. Since we're told the plant is growing at a constant rate, this shows the bean plant is growing 2 centimeters per day. We can represent this with y = 2x. (After 10 days, the bean plant will be 20 centimeters, after 20 days, the bean plant will be 40 centimeters, etc.)

However, this is not completely true yet. As you can see, after the first 10 days the plant is not 20 centimeter, it's 25 centimeters. We already know the rate in which the plant is changing, but now we need to find the height that the plant was originally, before it started growing.

After the first 10 days, the plant is 25 centimeters tall. Since we know that the plant is growing 2 centimeters per day, we can subtract 20 from 25 to find the original height of the bean plant.

25 - 20 = 5
The bean plant was originally 5 centimeters.

This makes our final equation y = 2x + 5.
2x is the slope, and 5 is the y intercept.

Hope this helps1!
5 0
3 years ago
Other questions:
  • Lydia is having a party on Saturday she decides to write a riddle order invitations to describe your house number on Cypress Str
    7·1 answer
  • There is a picture once you have join tutor ​
    14·2 answers
  • A tree casts a shadow 18 feet long. At the same time, a vertical rod 12 feet high casts a shadow 4 feet long. How long is the tr
    12·1 answer
  • PLEASE HELP I GIVE THANKS
    5·1 answer
  • What is distance=12mi;time=2h;rate
    10·1 answer
  • Helppooooopopopppppp
    8·1 answer
  • Solve the inequality:<br> 2x - 6 &gt; 12
    6·2 answers
  • I need help plz ASAP
    5·2 answers
  • Question 1 of 25
    7·1 answer
  • Please please please please help meeee l don’t understand I need the working out
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!