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kotegsom [21]
3 years ago
13

:v. holliwud was a country​

Mathematics
1 answer:
larisa [96]3 years ago
6 0
B C AND F IS THE ANSWER
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A random sample of 384 people in a mid-sized city (city one) revealed 112 individuals who worked at more than one job. A second
Svetlanka [38]

Answer:

99% confidence interval is:

(0.00278 < P1 - P2< 0.15921)

Step-by-step explanation:

For calculating a confidence intervale for the difference between the proportions of workers in the two cities, we calculate the following:

[(p_{1} - p_{2}) \pm z_{\alpha/2} \sqrt{\frac{p_{1}(1-p_{1})}{n_{1}} + \frac{p_{2}(1-p_{2})}{n_{2}} }

             Where  p_{1} : proportion sample of individuals who worked      

                                                     at more than one job in the city one

                           n_{1}: Number of respondents in the city one

                           p_{1} : proportion sample of individuals who worked      

                                                     at more than one job in the city two

                           n_{1}: Number of respondents in the city two

Then

α = 0.01 and α/2 = 0.005

and z_{\alpha/2} = 2.575

p_{1} = \frac{112}{384} = 0.2916

p_{2} = \frac{91}{432} = 0.2106

n_{1}= 384  and n_{2}= 432

The confidence interval is:

[(0.2916 - 0.2106) \pm 2.575 \sqrt{\frac{0.2916(1-0.2916)}{384} + \frac{0.2106(1-0.2106)}{432} }

(0.00278 < P1 - P2< 0.15921)

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