Answer:
130
Step-by-step explanation:
10 x 13 = 130
13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 = 130
The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.
<u>Step-by-step explanation:</u>
- The equation for the maximum speed, s is given by s²= (16/9)x
- where, x is the length of the water line in feet.
It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.
The question is asked to find the maximum speed when the length of the water is 30 feet.
Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.
<u>Now, calculating the maximum speed :</u>
s² = (16/9)(30)
s² = 480 / 9
s² = 53.3
Taking square root on both sides,
s = √53.3
s = 7.3
The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.
Answer:
D
Step-by-step explanation:
If its right let me know I think this is right
Answer:Yolanda served 13 orders.
Ahmad served 19 orders.
Hong served 38 orders.
Step-by-step explanation:
Let x represent the number of orders that Ahmad served.
Yolanda served 6 fewer orders than Ahmad. This means that the number of orders that Yolanda served is x - 6
Hong served 2 times as
many orders as Ahmad. This means that the number of orders that Hong served is 2x
Yolanda, Hong, and Ahmad served a total of 70 orders Monday at the school cafeteria. This means that
x - 6 + x + 2x = 70
4x - 6 = 70
4x = 70 + 6 = 76
x = 76/4 = 19
Hong served 2 × 19 = 38
Yolanda served 19 - 6 = 13
Well all i can tell you is to do tis
6.6/5.00=1.32
but..... 6.6 is also equal to 6,600,000 so divide 6,600,000 by 5.00= 1,320,000 is your answer