Question

A falling object traveled can be moldeled by equation d= 1/2 at 2 where a is acceleration and t time fallen how do you finf t in terms of a and d ex. T= square 2d/a

Answer 1

Answer:

$t = \sqrt{\frac{2d}{a}}$

Step-by-step explanation:

Given

$d = \frac{1}{2}at^2$

Required

Solve for t

To do this, we simply make t the subject of formula;

This is done as follows:

$d = \frac{1}{2}at^2$

Multiply both sides by 2

$2 * d = \frac{1}{2}at^2 * 2$

$2d = at^2$

Divide both sides by 2

$\frac{2d}{a} = \frac{at^2}{a}$

$\frac{2d}{a} = t^2$

Take square root of both sides

$\sqrt{\frac{2d}{a}} = t$

Reorder

$t = \sqrt{\frac{2d}{a}}$