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Gwar [14]
3 years ago
6

HElp Me PLaesssssssssssssssssssssssssssss

Mathematics
1 answer:
Nataliya [291]3 years ago
8 0
I think it is the first one
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Which expressions are equivalent to when x0? Check all that apply.
Genrish500 [490]
We have that

\frac{(x+4)}{3} / \frac{6}{x} = \frac{x*(x+4)}{3*6} \\ \\ = \frac{( x^{2} +4x)}{18}

therefore

case a) 
\frac{(x+4)}{3} * \frac{x}{6}
Is equivalent

case b) 
\frac{6}{x} * \frac{(x+4)}{3}
Is not equivalent

case c) 
\frac{x}{6} * \frac{(x+4)}{3}
Is  equivalent

case d) 
\frac{(2 x^{2} +4x)}{6}
Is not equivalent

case e) 
\frac{(2 x^{2} +4x)}{18}
Is equivalent

Hence

the answer is

\frac{(x+4)}{3} * \frac{x}{6}

\frac{x}{6} * \frac{(x+4)}{3}

\frac{(2 x^{2} +4x)}{18}
3 0
3 years ago
Read 2 more answers
What additional information is necessary to prove that SILY is a parallelogram
kirza4 [7]

Answer:

Are the sides parallel?

Step-by-step explanation:

8 0
4 years ago
Order the fractions from least to greatest.
pantera1 [17]

Answer:

that would be c

Step-by-step explanation:

is because it is least to greatest I hope this helps you

6 0
2 years ago
Prove the following identity true. Show work.
yulyashka [42]

Answer:

The  Pythagorean identity states that

\sin^2 t + \cos^2 t = 1

Using that we can rewrite the left denominator as:

1 - \sin^2 t

Which can be factored as

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The numerator we can expand as:

(1 - \sin t)(1 - \sin t)

On the right hand side, let's multply numerator and denominator with (1 - sin t):

The total formula then becomes:

\dfrac{(1-\sin t)(1-\sin t)}{(1 - \sin t)(1 + \sin t)} = \dfrac{(1-\sin t)(1 - \sin t)}{(1+\sin t)(1 - \sin t)}

There you go... left and right are equal.

3 0
3 years ago
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How do you graph the equation y=|x|?
Rufina [12.5K]

graph looks like the letter v

2 around x means no matter what value x is y will be positive

plot points would be

(-2,2) (-1,1) (0,0) (1,1) (2,2)

8 0
3 years ago
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