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Andrej [43]
3 years ago
10

How do we prove that a line is a tangent of a circle ​

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Answer:

if the line makes an angle of 90° with the radius of the circle at the point of contact of the tangent and the circle

You might be interested in
What are the values of the function y=-2 x-4 for x=0,1,2,3
iragen [17]

Answer:

read description

Step-by-step explanation:

y=-2(0)-4    ANSWER: y=-4

y=-2(1)-4     ANSWER: y=-6

y=-2(2)-4    ANSWER: y=-8

y=-2(3)-4    ANSWER: y=-10

7 0
3 years ago
What is the answer to |4r−12| , if r<3?
Sav [38]

Answer:

Step-by-step explanation:

|4r−12| = -(4r-12)  when 4r-12< 0

4r< 12 so r<3

7 0
3 years ago
En la preparación de un perfume se cuenta con dos tipos de esencia base: 1600 ml de una y 1680 ml de otra. Se quiere envasarlas,
Lostsunrise [7]

Answer:

33,600 frascos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encuentre y enumere los múltiplos de 1600 y 1680 hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

Múltiplos de 1600:

1600, 3200, 4800, 6400, 8000, 9600, 11200, 12800, 14400, 16000, 17600, 19200, 20800, 22400, 24000, 25600, 27200, 28800, 30400, 32000, 33600, 35200, 36800

Múltiplos de 1680:

1680, 3360, 5040, 6720, 8400, 10080, 11760, 13440, 15120, 16800, 18480, 20160, 21840, 23520, 25200, 26880, 28560, 30240, 31920, 33600, 35280, 36960

Por lo tanto,

LCM (1600, 1680) = 33,600

La menor cantidad de frascos necesarios es 33,600 frascos.

4 0
3 years ago
If the 50th and 51st terms of an arithmetic sequence are 140 and 142, find the 1st term
morpeh [17]

Answer:

The first term is 42.

Step-by-step explanation:

The common difference is 142  - 140 = 2 so we have

50th term = a1 + 2(50 -1) = 140    where a1 is the first term

a1 + 98 = 140

a1 = 140 - 98 =  42.

4 0
4 years ago
What is the value of -16?
timama [110]

Answer:

the answer would be -4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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