Answer:
y > 1/2x - 1
First, draw the dashed line y = 1/2x - 1 (slope intercept ; y = mx + b).
Start at -1 on the y-axis, and continue going 2 units to the right, and 1 unit up for the right side of the graph.
Then starting at -1 on the y-axis, continue going 2 units to the left, and 1 unit down for the left side of the graph.
Explanation:
Convert standard form (Ax + By = C) by isolating y from the rest of the equation.
Ax + By = C → y = -Ax/B + C/B → y = mx + b.
Given a standard form equation in inequality form,
x - 2y < 2.
Set it to slope-intercept as an inequality to find the slope and y-intercept.
When negating (making opposite) a variable, you flip the inequality.
x - 2y < 2 → x - 2y - x < 2 - x → -2y < -x + 2 → 2y > x - 2 → <u>y > 1/2x - 1</u><u>.</u>
Answer:
D to C
Step-by-step explanation:
The radius is half the diameter or the center point to the edge (circumference)
The only that has the shape of the one below.
y = -4(x^3 + 7x^2+8x - 16)
Let x = 1
y = - 4(1 + 7 + 8 - 16)
y = 0
y = -4(x -1)(x^2 + 8x + 16)
y = -4(x - 1)(x + 4)^2
Answer:
The graph is attached Below and the plotting is given below.
Step-by-step explanation:
Given:
-9x + 6y = 18
Solution:
To draw a line on a graph the required minimum two points but here we will have three points as point A, point B, and point C.
For point A
Put x = -4 in the given equation we get
-9×-4 + 6y = 18
6y = 18-36
∴ 
∴ Point A ≡ ( -4, -3 ).
For point B
Put x = -2 in the given equation we get
-9×-2 + 6y = 18
6y = 18 - 18
6y = 0
∴ 
∴ Point B ≡ ( -2, 0 ).
For point C
Put x = 0 in the given equation we get
-9×0 + 6y = 18
6y = 18
∴ 
∴ Point C ≡ ( 0, 3 ).
Now we have Point A ,B and C join it and you will have Line.