I wanna say threads bc cores r processors. And one can run multiple threads. Double check tht :)
Answer:
C++ code explained below
Explanation:
#include<bits/stdc++.h>
#include <iostream>
using namespace std;
int FiboNR(int n)
{
int max=n+1;
int F[max];
F[0]=0;F[1]=1;
for(int i=2;i<=n;i++)
{
F[i]=F[i-1]+F[i-2];
}
return (F[n]);
}
int FiboR(int n)
{
if(n==0||n==1)
return n;
else
return (FiboR(n-1)+FiboR(n-2));
}
int main()
{
long long int i,f;
double t1,t2;
int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};
cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;
cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;
for(i=0;i<16;i++)
{
clock_t begin = clock();
f=FiboR(n[i]);
clock_t end = clock();
t1=double(end-begin); // elapsed time in milli secons
begin = clock();
f=FiboNR(n[i]);
end = clock();
t2=double(end-begin);
cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds
}
return 0;
}
Answer:
Option d pretest
Explanation:
Given the pseudocode:
- do stepA
- do stepB
- if conditionC is true
- then do stepD
- else
- do stepE
- end if
- while conditionF is true
- do stepG
- end while
The pseudocode above shows that there is a pretest before some codes are executed. For example, line 3 check if condition is true then only execute stepD otherwise execute stepE. Line 8 check if conditionF is true then repeatedly execute stepG. These are examples of pretest a condition will must be met (pretest passed) before a block of codes can be executed. This pretest can be seen in if-else statements and also the while condition.
Explanation:
not A or D,
about B and C I'm not sure
Default tab stops are set in word every 1/2 inch so your correct answer is C :)
