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dalvyx [7]
3 years ago
9

Help me with math someone

Mathematics
1 answer:
fiasKO [112]3 years ago
4 0
My dad beats me everyday and he told me that I’m a failure
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IF U CAN SOLVE THIS I LITERALLY LUV U ILL GIVE U BRAINLIEST 5 STARS AND A THANKSSS OMG PLS IN 10 MINUETSSS :c
gogolik [260]

Answer:

determination and family

7 0
3 years ago
What equation represents y=2x^2+24x+85 in vertex form
Andrej [43]
Y=a(x-h)^2+k

vertex form is basically completing the square

what you do is
for
y=ax^2+bx+c
1. isolate x terms
y=(ax^2+bx)+c
undistribute a
y=a(x^2+(b/a)x)+c
complete the square by take 1/2 of b/a and squaring it then adding negative and postive inside
y=a(x^2+(b/a)x+(b^2)/(4a^2)-(b^2)/(4a^2))+c
complete square
too messy \
anyway

y=2x^2+24x+85
isolate
y=(2x^2+24x)+85
undistribute
y=2(x^2+12x)+85
1/2 of 12 is 6, 6^2=36
add neagtive and postivie isnde
y=2(x^2+12x+36-36)+85
complete perfect square
y=2((x+6)^2-36)+85
distribute
y=2(x+6)^2-72+85
y=2(x+6)^2+13

vertex form is
y=2(x+6)^2+13
8 0
3 years ago
What is the nth term rule of the linear sequence below?<br>13, 7, 1, -5, -11,...​
vredina [299]
Sry I don’t know try Socratic
8 0
3 years ago
What should be added in the polynomial x3-6x2+11x+8 so that it is completely divisible by 1-3x +x2
yanalaym [24]

Answer:

The value to be added to the polynomial x³ - 6·x² + 11·x + 8 so that it is completely divisible by 1 - 3·x + x² is -(x + 11)

Step-by-step explanation:

By long division, we have;

{\left ({x^{3}-6x^{2}+11x+8}  \right )\div 1 - 3x + x^{2}} = x - 3

-(x³ - 3·x² + x)

     -3·x² + 10·x + 8

     -(-3·x² + 9·x -3)

                  x + 11

Therefore, -(x + 11) should be added to the polynomial x³ - 6·x² + 11·x + 8 so that it is completely divisible by 1 - 3·x + x².

That is  (x³ - 6·x² + 11·x + 8 - x - 11) ÷ (1 - 3·x + x²) = x - 3.

5 0
3 years ago
Somebody, Anybody please help
taurus [48]
The answer should be 390=60s, assuming s is the number of shelves he would need.

By the way, if you want the answer using this formula:
390=60s
390/60=s
6.5=s
s=6.5
8 0
3 years ago
Read 2 more answers
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