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timofeeve [1]
2 years ago
9

A circle has a diameter of 26 units. What is the area of the circle to the nearest

Mathematics
1 answer:
denis23 [38]2 years ago
8 0

Answer:

b

Step-by-step explanation:

area = pie x radius(2)

         = 3.142 x 13 (2)

          = 530.998

You might be interested in
A) Enter the corresponding values on the quadratic formula:
ollegr [7]

The answer is a = 0, b = -5, and c= 39.

<u>Step-by-step explanation</u>:

<u>step 1</u> :

A quadratic equation means that it should have at least one squared term.

<u>step 2</u> :

The standard form is ax² + bx + c = 0.

<u>step 3</u> :

The solution to the quadratic equation is usually written in the form

x = (-b ± √(b2 − 4ac))/(2a)

where a = coefficient of x^2

           b = coefficient of x

          c = constant term

<u>step 4</u> :

The given equation is -5x +32.

∴ The answer is a = coefficient of x^2 = 0

                           b = coefficient of x = -5

                          c = constant term = 39

7 0
3 years ago
For t=2 , 14t−3t is equal to ____? and 3t−14t is equal to ____?
const2013 [10]

Answer:

14t-3t=22

  1. 3t-14t= -22
  2. where there is t multiply by 2
8 0
2 years ago
Three corporations each own land. Corporation A owns 3.2 × 105 acres, corporation B owns 4 × 104 acres, and corporation C owns 4
elena-14-01-66 [18.8K]
First of all, we know that
Corporation A owns 3.2 × 10^5 acres
Corporation B owns 4×10^4 acres
Corporation C owns 4.3×10^5 acres
To compare which corporation owns the most land, we need to have the same unit of exponent which is 10^4, so we need to change Corporation A and Corporation C:
Corporation A: 3.2×10^5
Corporation A: 32×10^4
Corporation C: 4.3×10^5
Corporation C: 43×10^4
In this case, compare all three corporation. We see that Corporation C owns the most land.
Lastly,
To find “ How many times greater is corporation A’s land than corporation B’s land ", take:
Corporation A / Corporation B
=32×10^4/4×10^4
=32/4×10^4/10^4
=8×10^4-4
=8×10^0
=8×1
=8 times is your final answer. Hope it help!
5 0
3 years ago
Read 2 more answers
What is the area of the parallelogram above! A.54 B.36.36 C.54.55 D 9​
Ne4ueva [31]

9514 1404 393

Answer:

  A.  54

Step-by-step explanation:

The area of a parallelogram is the product of its base length (9) and height (6). The height is measured perpendicular to the base. That is why the height it 6, not 6.06.

  A = bh = 9·6 = 54

3 0
3 years ago
How many terms of the series of - 3+0+3+6+9+...are needed to give a sum of 105?​
dolphi86 [110]

Answer:

10

Step-by-step explanation:

Remember that the formula for the sum of an arithmetic series is:

S=\frac{k}{2}(a+x_k)

Where k is the number of terms, a is the initial term, and x_k is the last term of the series.

We essentially want to find k, the number of terms, given that the sum S is equal to 105. So, substitute 105 into our equation:

105=\frac{k}{2}(a+x_k)

To do so, we need to final term x_k. We don't know what it is yet, but that doesn't matter. All we need to do is to write it in terms of k. First, remember that the standard form for the explicit formula of an arithmetic sequence is:

x_n=a+d(n-1)

Where a is the first term, d is the common difference, and n is the nth term.

From our sequence, we can see that the first term is -3.

Also, we can determine that our common difference is +3, since each subsequent term is 3 <em>more</em> than the previous one. -3+3 is 0, 0+3 is 3, 3+3 is 6, and so on.

Therefore, our explicit formula is:

x_n=-3+3(n-1)

Therefore, our final term, x_k, will be if we substitute k for n. So, we can acquire the equation:

x_k=-3+3(k-1)

Now that we know what x_k is, we can substitute that into our original equation:

105=\frac{k}{2}(a+x_k)

Substitute the equation into x_k. Also, let's substitute -3 (our first term) for a. So:

105=\frac{k}{2}(-3+(-3+3(k-1)))

And now, all we have to do is to solve for k.

First, distribute the 3:

105=\frac{k}{2}(-3+(-3+3k-3))

Add within the parentheses:

105=\frac{k}{2}(3k-9)

Multiply both sides by 2. This removes the fraction on the right:

210=k(3k-9)

Distribute. We will get a quadratic:

210=3k^2-9k

So, let's solve for k. Let's divide everything by 3:

70=k^2-3k

Subtract 70 from both sides:

0=k^2-3k-70

Factor. We can use -10 and 7. So:

0=(k-10)(k+7)

Zero Product Property:

k-10=0\text{ or } k+7=0

Solve for k for each equation:

k=10\text{ or } k=-7

-7 doesn't make sense (we can't have -7 terms). Remove that solution. So, we are left with:

k=10

Therefore, the number of terms we have in our series for our sum to be 105 is 10.

And we're done!

4 0
3 years ago
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