Answer:
q= 2,550
Step-by-step explanation:
Giving the following information:
The demand function is q=-110p+7500.
<u>When the price is 0, the demand q is 7,500 units:</u>
p= 0
q= -110*0 + 7,500= 7,500
<u>Now, when the price is $45, the demand is:</u>
p= $45
q= -110*45 + 7,500
q= -4,950 + 7,500
q= 2,550
Slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
we are given the points (-2,7) and (x,2)
slope is -1/3
so
(x,y)
(-2,7) and (x,2)
x1=-2
y1=7
x2=x
y2=2
slope=(2-7)/(x-(-2))=-1/3
slope=(-5)/(x+2)=-1/3
multiply both sides by (-3)(x+2) (basically cross multiply)
15=x+2
minus 2 both sides
13=x
x=13
the value of x is 13
Answer:
e
Step-by-step explanation:
Answer:
(c) x = 2 and x = -8
Step-by-step explanation:
The rules of logarithms let you rewrite this as a quadratic equation. That equation will have two (2) potential solutions. We know from the domain of the log function that any negative value of x will be an extraneous solution.
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The rules of logarithms that apply are ...

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<h3>take antilogs</h3>
We can rewrite the equation so that only one logarithm is involved. Then we can take antilogs.

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<h3>solve the quadratic</h3>
Adding (6/2)² = 9 to both sides will "complete the square."
16 +9 = x² +6x +9 . . . . . . . add 9
25 = (x +3)²
±√25 = x +3 = ±5 . . . . . take the square root(s)
x = -3 ±5 = {-8, +2}
The two potential solutions are x = 2 and x = -8.
-16x+40 is the solution of this problem.