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crimeas [40]
3 years ago
11

Help show work please

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
5 0

Answer:

8x squared

Step-by-step explanation:

all you do is multiply the 4 and 2 to get the 8 and the x's multiply together causing it to square it making it 8x squared

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Determine the projection of w onto u
natali 33 [55]

Answer:

c. 6.2i - 4.2j

Step-by-step explanation:

The vector projection when the angle θ not known can be calculated  using the following property of the dot product:

proj_uv=\frac{u\cdot v}{||u||^2} u

Where the dot product of two vectors is given by:

u\cdot v= $$\sum_{i=1}^{n} u_iv_i= u_1v_1+u_2v_2+...+u_nv_n$$

And the magnitude of a vector is given by:

||u||=\sqrt{u_1^2+u_2^2+...+u_n^2}

Using the previous definition, let's calculate the projection of w onto u:

First let's calculate the dot product between w and u:

u\cdot w =(9*19)+(-6*15)=171-90=81

Now let's find the magnitude of u:

||u||=\sqrt{9^2+(-6)^2} = 3 \sqrt{13}

So:

||u||^2=117

Therefore:

proj_uw=\frac{u\cdot w}{||u||^2} u=\frac{81}{117} \langle9,-6\rangle=\langle6.23,-4.14\rangle\approx6.2i-4.2j

5 0
3 years ago
Read 2 more answers
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