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Sati [7]
3 years ago
9

2(6x + 6)

Mathematics
2 answers:
Sever21 [200]3 years ago
5 0

Answer:

Look at picture!


Hope this helped!


Maslowich3 years ago
4 0
3(x - 2) = 3x -6
3(4x + 4)= 12x + 12
2x + 6
4(x +3) 4x + 12
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The equation of line q is 5y - 4x = 10. Write the standard fom of the equation of the line that fits the following description:
kumpel [21]
<h3>Answer:  -4x+5y = 100</h3>

===================================================

Explanation:

The given equation is the same as -4x+5y = 10

It is of the form Ax+By = C, where A = -4, B = 5, C = 10

Anything parallel to Ax+By = C is of the form Ax+By = D. The only difference is the C has changed to a D.

This means anything parallel to -4x+5y = 10 is -4x+5y = D, where D is not equal to 10, but it could be any other number.

Plug in the coordinates of (-15,8) to find the value of D

-4x+5y = D

-4(-15)+5(8) = D

60+40 = D

100 = D

D = 100

We have -4x+5y = D update to -4x+5y = 100

The equation -4x+5y = 100 is parallel to -4x+5y = 10, and it goes through (-15,8)

Parallel lines have the same slope, but different y intercepts.

Note how Ax+By = C has a slope of m = -B/A. This means A cannot be zero.

7 0
3 years ago
HELPPPPPP i will give brainliest!!!!!
Katen [24]

Answer:

10-5=5 answer is 8^5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLS HELP OLL GIVE BRAINLIEST
Rudiy27

Answer:

yes they are the same

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The pair of points 6, Y and 10, -1 light on a line with a slope of 1/4 what is the value of Y
andrezito [222]

\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{y})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-y}{10-6}=\stackrel{\stackrel{given}{\downarrow }}{\cfrac{1}{4}}\implies \cfrac{-1-y}{4}=\cfrac{1}{4} \\\\\\ 4(-1-y)=4\implies -1-y=\cfrac{4}{4}\implies -1-y=1\implies -2=y

3 0
3 years ago
Please answer both thank you​
jeyben [28]

Answer:

7.

Solution given;

male=15

female=27

1st term=5*3

2nd term=3*3*3

now

Highest common factor=3

So

<u>The</u><u> </u><u>maximum</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>groups</u><u> </u><u>that</u><u> </u><u>the</u><u> </u><u>teacher</u><u> </u><u>can</u><u> </u><u>make</u><u> </u><u>is</u><u> </u><u>3</u><u>.</u>

<u>and</u><u> </u><u>each</u><u> </u><u>team</u><u> </u><u>contains</u><u> </u><u>5</u><u> </u><u>male and</u><u> </u><u>9</u><u> </u><u>female</u><u>.</u>

7 0
3 years ago
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