Can someone help please? I need help
2 answers:
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Answer:
40%
Step-by-step explanation:
Given the result of the simulation below:
(5,5) (0,6) (9,6) (7,4) (9,1) (7,3) (0,4) (9,3) (2,9) (1,4)
(6,8) (5,3) (1,7) (1,7) (1,8) (3,5) (7,2) (2,1) (0,6) (1,8)
n(S)=20
- The numbers 0 to 6 represent a made free throw .
- The numbers 7 to 9 represent a missed free throw.
- Therefore, any result containing 7 to 9 does not satisfy our requirement that the player makes both throws.
Let Event A be the event that the player made both throws
The pairs in which the player made both throws are:
(5,5) (0,6) (0,4) (1,4) (5,3) (3,5) (2,1) (0,6)
n(A)=8
Therefore:
The probability that the player made both throws is 40%.
I wonder if you mean to write in place of
...
If you meant what you wrote, then we have
If you meant to write (the cube root of 256), then we could go on to have