Answer:
f(2n)-f(n)=log2
b.lg(lg2+lgn)-lglgn
c. f(2n)/f(n)=2
d.2nlg2+nlgn
e.f(2n)/(n)=4
f.f(2n)/f(n)=8
g. f(2n)/f(n)=2
Step-by-step explanation:
What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]
from a
f(n)=logn
f(2n)=lg(2n)
f(2n)-f(n)=log2n-logn
lo(2*n)=lg2+lgn-lgn
f(2n)-f(n)=lg2+lgn-lgn
f(2n)-f(n)=log2
2.f(n)=lglgn
F(2n)=lglg2n
f(2n)-f(n)=lglg2n-lglgn
lg2n=lg2+lgn
lg(lg2+lgn)-lglgn
3.f(n)=100n
f(2n)=100(2n)
f(2n)/f(n)=200n/100n
f(2n)/f(n)=2
the time will double
4.f(n)=nlgn
f(2n)=2nlg2n
f(2n)-f(n)=2nlg2n-nlgn
f(2n)-f(n)=2n(lg2+lgn)-nlgn
2nLg2+2nlgn-nlgn
2nlg2+nlgn
5.we shall look for the ratio
f(n)=n^2
f(2n)=2n^2
f(2n)/(n)=2n^2/n^2
f(2n)/(n)=4n^2/n^2
f(2n)/(n)=4
the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare
6.n^3
f(n)=n^3
f(2n)=(2n)^3
f(2n)/f(n)=(2n)^3/n^3
f(2n)/f(n)=8
the ratio will be times 8 the initial
7.2n
f(n)=2n
f(2n)=2(2n)
f(2n)/f(n)=2(2n)/2n
f(2n)/f(n)=2
Answer:
(-1 (3 y + 17))/2
Step-by-step explanation:
Simplify the following:
y/4 - (1 + 3/4) y - 12 + 1/2 + 1 + 2
Put 1 + 3/4 over the common denominator 4. 1 + 3/4 = 4/4 + 3/4:
y/4 - 4/4 + 3/4 y - 12 + 1/2 + 1 + 2
4/4 + 3/4 = (4 + 3)/4:
y/4 - (4 + 3)/4 y - 12 + 1/2 + 1 + 2
4 + 3 = 7:
y/4 - 7 y/4 - 12 + 1/2 + 1 + 2
Put each term in y/4 - (7 y)/4 - 12 + 1/2 + 1 + 2 over the common denominator 4: y/4 - (7 y)/4 - 12 + 1/2 + 1 + 2 = y/4 - (7 y)/4 - 48/4 + 2/4 + 4/4 + 8/4:
y/4 - (7 y)/4 - 48/4 + 2/4 + 4/4 + 8/4
y/4 - (7 y)/4 - 48/4 + 2/4 + 4/4 + 8/4 = (y - 7 y - 48 + 2 + 4 + 8)/4:
(y - 7 y - 48 + 2 + 4 + 8)/4
Grouping like terms, y - 7 y - 48 + 2 + 4 + 8 = (y - 7 y) + (4 + 2 + 8 - 48):
((y - 7 y) + (4 + 2 + 8 - 48))/4
y - 7 y = -6 y:
(-6 y + (4 + 2 + 8 - 48))/4
4 + 2 + 8 - 48 = -34:
(-34 - 6 y)/4
Factor -2 out of -6 y - 34:
(-2 (3 y + 17))/4
The gcd of -2 and 4 is 2, so (-2 (3 y + 17))/4 = ((2 (-1)) (3 y + 17))/(2×2) = 2/2×(-(3 y + 17))/2 = (-(3 y + 17))/2:
Answer: (-1 (3 y + 17))/2
Answer:
The answer is -20%
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
Rounding up 4.6 to the nearest whole tenth is 0
