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emmainna [20.7K]
3 years ago
6

What grade average is 79.2 out of 120​

Mathematics
2 answers:
slega [8]3 years ago
6 0
(79.2/120)x 100=66% the grade average is the amount over the total.
mina [271]3 years ago
3 0

Answer:

66%

Step-by-step explanation:

Divide 79.2 by 120 and multiply by 100

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3 X 4 + 4 = ______Immersive Reader (5 Points)
son4ous [18]

Answer:

16

Step-by-step explanation:

8 0
3 years ago
Solve the two-step equation 14=31.7-3x
ch4aika [34]

Answer: X = 5.9

Step-by-step explanation:

5 0
3 years ago
Help me lawd!!!!!!!jkdmfkfm
Klio2033 [76]
This is equivalent to:

(2.2533/2.59)(10^8/10^4)

(0.87)(10^4) which is:

0.87X10^4  which is equal to:  

0.87X10000 which is equal to:

8.7X1000  and since 1000=10^3 we can say:

8.7X10^3
6 0
3 years ago
Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.
fenix001 [56]

Answer:

The angle between vector \vec{u} = 5\, \vec{i} - 8\, \vec{j} and \vec{v} = 5\, \vec{i} + \, \vec{j} is approximately 1.21 radians, which is equivalent to approximately 69.3^\circ.

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

  • their dot products, and
  • the product of their lengths.

To be precise, if \theta denotes the angle between \vec{u} and \vec{v} (assume that 0^\circ \le \theta < 180^\circ or equivalently 0 \le \theta < \pi,) then:

\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}.

<h3>Dot product of the two vectors</h3>

The first component of \vec{u} is 5 and the first component of \vec{v} is also

The second component of \vec{u} is (-8) while the second component of \vec{v} is 1. The product of these two second components is (-8) \times 1= (-8).

The dot product of \vec{u} and \vec{v} will thus be:

\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}.

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both \vec{u} and \vec{v}:

  • \| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}.
  • \| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}.

<h3>Angle between the two vectors</h3>

Let \theta represent the angle between \vec{u} and \vec{v}. Apply the formula\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} to find the cosine of this angle:

\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}.

Since \theta is the angle between two vectors, its value should be between 0\; \rm radians and \pi \; \rm radians (0^\circ and 180^\circ.) That is: 0 \le \theta < \pi and 0^\circ \le \theta < 180^\circ. Apply the arccosine function (the inverse of the cosine function) to find the value of \theta:

\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ .

3 0
3 years ago
A reasonable estimate for a mass of a baby is
DerKrebs [107]
10 lb
well I could be wrong
3 0
3 years ago
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