3x - 2y = 1
2x + 2y = 4
Add the second equation to the first
5x = 5
2x + 2y = 4
Divide the first equation by 5
x = 1
2x + 2y = 4
Subtract the first equation from the second
x = 1
x + 2y = 3
Subtract the first equation from the second again
x = 1
2y = 2
Divide the second equation by 2
x = 1
y = 1
<h3>
So, the solution is x = 1 and y = 1 {or: (1, 1)} </h3>
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