Answer:
Whats the question ;-;
Step-by-step explanation:
Answer:
Therefore the required resulting equation is
6 x minus 15 y = negative 63.
Negative 15 x + 15 y = 90
Step-by-step explanation:
Given:
......................Equation ( 1 )
......................Equation ( 2 )
To Find:
Expression after multiplying to eliminate y term,
Solution:
So to eliminate 'y' term we need to multiply equation 1 by a constant 3 and equation 2 by a constant -5, such that equations becomes
.....( 1 )
.....( 2 )
so now by adding new equation one and two we can eliminate y term that means -15y and +15y will get cancel,
Therefore the required resulting equation is
6 x minus 15 y = negative 63.
Negative 15 x + 15 y = 90
Answer:8
Step-by-step explanation;Since you want to find the density but you already have the mass you do the inverse operation and divdie 56 by 7 and get 8.
Answer:
Step-by-step explanation:
NA = √[(- 4 - 1 )² + (- 3 - 2)²] = 5√2
AT = √[(8 - 1 )² + (1 - 2)²] = 5√2
TS = √[(3 - 8 )² + (- 4 - 1)²] = 5√2
NS = √[(- 4 - 3 )² + (- 3 + 4)²] = 5√2
NA = AT = TS = NS = 5√2
= (- 3 - 2) / (- 4 - 1) = 1 ........ <em>(1)</em>
= (- 4 - 1) / (3 - 8 ) = 1 ......... <em>(2)</em>
From (1) and (2) ⇒ NA║TS
= ( 1 - 2) / ( 8 - 1) = - 1 / 7 .......... <em>(3)</em>
= ( - 4 + 3) / ( 3 + 4) = - 1 / 7 .... <em>(4)</em>
From (3) and (4) ⇒ AT║NS
Thus, NATS is rhombus.
<u>Find fraction of snappers and catfish:</u>
1/3 + 2/9 = 3/9 + 2/9 = 5/9
<u>Find fraction of goldfish:</u>
1 - 5/9 = 4/9
4/9 = 40 goldfish
1/9 = 40 ÷ 4 = 10
9/9 = 10 x 9 = 90
Answer: 90 fish in the tank