All categories

2 years ago

What's 52 + 87 ( they deleted my other question lol ) I ain't never seen to pretty best friend's... Are we pretty?

Mathematics

1 answer:

Gnoma [55]2 years ago

6 0

Its 139, pretty sure u knew that, besides that, u guys r pretty and ik this joke i’ve seen it on tiktok

You might be interested in

A square has a perimeter of 36 millimeters, what is the area of the square

sveta [45]

81 millimeters. ........................

4 0

2 years ago

Please help soon and explain. I don’t know how to solve! Thank u!

dsp73

2/3 because you flip 3 coins and you want to get al least 2 heads!

4 0

2 years ago

jamie has taken three math tests. her scores were 85, 90, and 89. to get an average of 90 what must be the sum of all her tests

Zinaida [17]

Answer:

96 marks

Step-by-step explanation:

We know that the mean of a given amount of values is the sum of the values divided by the number of values

Let the marks in the fourth test = x marks

Mean of the values = 90

(85 + 90 + 89 + x) / 4 = 90

264 + x = 360

x = 96

Therefore, Jamie needs 96 marks in her 4th test to get a mean score of 90

5 0

2 years ago

The points (0, −6) and (−10, 4) lie on the graph of a linear function.

Montano1993 [528]

-10, -10 is the answer

3 0

2 years ago

Read 2 more answers

A study claims that college students spend an average of 4 hours or less studying per day. A researcher wants to check if this c

kirill115 [55]

<h2>Answer with explanation:</h2>

Let $\mu$ be the population mean.

By observing the given information, we have :-

$H_0:\mu\leq4\\\\H_a:\mu>4$

Since the alternative hypotheses is left tailed so the test is a right-tailed test.

We assume that the time spend by students per day is normally distributed.

Given : Sample size : n=121 , since n>30 so we use z-test.

Sample mean : $\overline{x}=3.15$

Standard deviation : $\sigma=1.2$

Test statistic for population mean :-

$z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

$\Rightarrow\ z=\dfrac{3.15-4}{\dfrac{1.2}{\sqrt{121}}}\\\\\Rightarrow\ z=-7.79166666667\approx-7.79$

Critical value (one-tailed) corresponds to the given significance level :-

$z_{\alpha}=z_{0.1}=1.2816$

Since the observed value of z (-7.79) is less than the critical value (1.2816) , so we do not reject the null hypothesis.

Hence, we conclude that we have enough evidence to accept that the college students spend an average of 4 hours or less studying per day.

4 0

2 years ago