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2 years ago

What's 52 + 87 ( they deleted my other question lol ) I ain't never seen to pretty best friend's... Are we pretty?

Mathematics

1 answer:

Gnoma [55]2 years ago

6 0

Its 139, pretty sure u knew that, besides that, u guys r pretty and ik this joke i’ve seen it on tiktok

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Suppose a number is rounded to the nearest hundred thousand. What is a number greater than 700,000 that rounds to 700,000?

tatiyna

Any number greater than 700,000 with ten-thousands digit 1 through 4 will round down to 700,000. For example, 748,235 will round to 700,000.

5 0

3 years ago

This table shows the heights of four boxes that need to be mailed.

Ksenya-84 [330]

The answer to the question is B.

5 0

3 years ago

A circle with a radius of 5 cm has an area of 25π cm2. Which is the best approximation for the area of one-half of this circle?

kotegsom [21]

Answer:

Step-by-step explanation:

π=3.14159...

Full circle are 25π cm² = 25*3.14=78.5 cm²

Half 78.5 cm²/2 = 39.25 cm²

4 0

2 years ago

I’m working on 3 and 4 only maybe if I can have some explanation so I can understand and do more of these next week.

guapka [62]

4.b.

Answer: See below.

Step-by-step explanation:

<h2>For the equation f(x) = 2x</h2>

3.a. f(6) means use x = 6 in the equation f(x) = 2x

so f(6) would be f(6)= 2(6)

f(6) = 12

3.b. f(-11) = 2(-11)

f(-11) = -22

3.c. f(2.75) = 2(2.75)

f(2.75) = 5.5

3.d. This is turned around. We are told f(x)=20, so what would x need to be for f(x) to be 20? Since f(x) = 2x, we can say 20 = 2x. Therefore x = 10

f(10) = 20

The rest of (3) are solved in the same fasion.h

<h2>For the equation f(x)= 5x+50</h2>

4.a. f(7) = 5(7)+50

f(7) = 85

4.b. f(-12)

f(-12) = 5*(-12)+50

f(-12) = -60

Continue in the same fashion for these types of problems.

7 0

2 years ago

Which two equations are true?(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)=6.6×10−10 (6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.

tiny-mole [99]

let me edit your question as:

Which two equations are true?

Eq1:

(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)

Eq2:

6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)

Eq3:

2.7×103(7.5×106)−(2.5×106)=5×100

Answer:

No one is true

Step-by-step explanation:

let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.

Using PEMDAS rule we are simplifying the equations as;

Eq1:

$(2*10-4)+(1.5*10-4)=3.5*10-4(3*10-5)+(2.2*10-5)\\(16)+(11)=35-4(25)+(17)\\27=35-100+17\\27=-48\\$

Eq2:

$6.6*10-10(6.3*10-1)-(2.1*10-1)=3*10-1(5.4*103)-(2.7*103)\\66-10(62)-(20)=30-1(556.2)-278.1\\66-620-20=30-556.2-278.1\\-574=-804.1$

Eq3:

$2.7*103(7.5*106)-(2.5*106)=5*100\\221089.5-265=500\\220824.5=500\\$

we observed that none of the equation has two same values on both sides thus none of the three equations is true.

Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true

8 0

3 years ago