The sum of 4 times one number and 3 times a second number is 64. If the sum of the two numbers is 19, find the two numbers.
1 answer:
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To solve this system of linear equations we need a little trick called elimination steps are below
we are given the following system of equations
if you look at the x variables in both equations you can see that we can easily eliminate them by multiplying the bottom equation by -4 as so
simplify and we get
now we can combine like terms on each side with the x's cancelling and get
now divide off -35
great now we can go back to our original system and pick a equation and substitute y back in to find x lets use
so now we substitute y and get
now we put x and y into one coordinate (x,y)
so now our FINAL ANSWER IS
(-17,-1)
we are given the following system of equations
if you look at the x variables in both equations you can see that we can easily eliminate them by multiplying the bottom equation by -4 as so
simplify and we get
now we can combine like terms on each side with the x's cancelling and get
now divide off -35
great now we can go back to our original system and pick a equation and substitute y back in to find x lets use
so now we substitute y and get
now we put x and y into one coordinate (x,y)
so now our FINAL ANSWER IS
(-17,-1)