The sum of 4 times one number and 3 times a second number is 64. If the sum of the two numbers is 19, find the two numbers.

1 answer:

4 0

A) 4*x + 3*y = 64
B) x + y = 19
B) x = 19 - y Substituting B into A
A) 4*(19 -y) + 3*y = 64
76 -4y + 3y = 64
-y = -12
y =12
x = 7

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