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docker41 [41]
3 years ago
15

FACTORISE 16x^2-y^2+4yz-4z^2​

Mathematics
1 answer:
Vadim26 [7]3 years ago
5 0

Answer:

uhm i think ive witten the questions but not the exact one just the factorise numbers are the same, i uploaded a picture.

Step-by-step explanation:

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Could somebody please help me with this?
BARSIC [14]

For this problem, we are going to use the Remainder Theorem. This says that for x - n to be a factor of a polynomial p(x), then p(n) = 0. Essentially, it says that x - n is a factor if when you substitute n into the polynomial you get a result of 0.


Thus, in our case, when we substitute x = 2 into the polynomial, we should get an answer of 0 if x - 2 is a factor of the polynomial. Given this information, we can solve for c:

p(2) = 2^3 - 4(2^2) + 2c + 2 = 0

8 - 16 + 2c + 2 = 0

2c - 6 = 0

2c = 6

c = 3


The solution is c = 3.

7 0
3 years ago
Read 2 more answers
2s+t=r solve for t rearrange the variables
DedPeter [7]

Answer:

Step-by-step explanation:

2s + t = r

t = r - 2s

8 0
2 years ago
for what value of k, the line joining 3x-ky+7=0 is perpendicular to the line joining (4 ,3) and ( 5, -3).
Schach [20]

Answer:

  • k = 18

=========

<h2>Given</h2>

<h3>Line 1</h3>
  • 3x - ky + 7 = 0

<h3>Line 2</h3>
  • Passing through the points (4, 3) and (5, - 3)

<h2>To find</h2>

  • The value of k, if the lines are perpendicular

<h2>Solution</h2>

We know the perpendicular lines have opposite reciprocal slopes, that is the product of their slopes is - 1.

Find the slope of line 1 by converting the equation into slope-intercept from standard form:

<u><em>Info:</em></u>

  • <em>standard form is ⇒ ax + by + c = 0, </em>
  • <em>slope - intercept form is ⇒ y = mx + b, where m is the slope</em>

  • 3x - ky + 7 = 0
  • ky = 3x + 7
  • y = (3/k)x + 7/k

Its slope is 3/k.

Find the slope of line 2, using the slope formula:

  • m = (y₂ - y₁)/(x₂ - x₁) = (-3 - 3)/(5 - 4) = - 6/1 = - 6

We have both the slopes now. Find their product:

  • (3/k)*(- 6) = - 1
  • - 18/k = - 1
  • k = 18

So when k is 18, the lines are perpendicular.

4 0
2 years ago
Please help me with the 3rd question!!! I'll give you 91 points now, please.
saw5 [17]

Answer:

At the end of the day 797 lockers were closed.

Step-by-step explanation:

So first of all you need to find out how many even numbers there are from 1-900 (which is 450) so you know that 450 are open. In the 3 multiplication tables every second number is even so you know that half of the 450 lockers that was opened was closed again: this meant that 225 lockers remained open.

You also know that every number in the 4 multiplication tables is the second number in the 2 multiplication tables so half of them are closed but you also know that the 900th locker was opened so now you have 113.

So to conclude you do 900-113 which gives you 797 (this is because 113 is the amount of lockers that is open)

3 0
3 years ago
College courses taken in high school for which students automatically receive both high school and college credits is called ___
lina2011 [118]

The answer is D. Dual enrollment courses

5 0
3 years ago
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