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3 years ago

FACTORISE 16x^2-y^2+4yz-4z^2

Mathematics

1 answer:

Vadim26 [7]3 years ago

5 0

Answer:

uhm i think ive witten the questions but not the exact one just the factorise numbers are the same, i uploaded a picture.

Step-by-step explanation:

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Solve For X

bazaltina [42]

$\frac{3ax+2b}{c}=4d\ \ \ \ \ \ |multiply\ both\ sides\ by\ "c"\\\\3ax+2b=4cd\ \ \ \ \ \ |subtract\ 2b\ from\ both\ sides\\\\3ax=4cd-2b\ \ \ \ \ \ |divide\ both\ sides\ by\ 3a\\\\\boxed{x=\frac{4cd-2b}{3a}}$

7 0

3 years ago

Each point on the edge of a circle is equidistant from the center of the circle. The center of a circle is located at (6,3). Whi

photoshop1234 [79]

Good evening

Answer:

Step-by-step explanation:

Suppose M(x , y) is a point of the circle of center (6,3) and radius 10 and M is also a point of the y-axis then the coordonates of M should verify these two equations at the same time:

$\left \{ {(x-6)^{2} +(y-3)^2=10^{2} } \atop {x=0}} \right.$

Then

(0-6)² + (y-3)² = 100

then

36 + (y-3)² = 100

then

(y-3)² = 100 - 36

= 64

then

|y-3| = 8

then

y - 3 = 8 or y - 3 = -8

then

y = 11 or y = 5

then the only points that are on the edge of the circle and on y-axis are:

(0 , 5) and (0 , 11).

3 0

3 years ago

Read 2 more answers

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 86m long and 64m wide. F

KIM [24]

To solve this problem, we have to find the area of the semi circles and the area of the rectangle and add them up together.

The area of the field is equal to 8719.36m^2

<h3>Area of the Field</h3>

Let us start by finding the area of the rectangle.

Data;

width = 86m
length = 64m

Area of a rectangle is given as

$a = length * width \\a = 86 * 64\\a = 5504m^2\\$

The area of the rectangle is 5504m^2

Area of the semicircle

The formula of a semi circle is given as

$A = \frac{1}{2} \pi r^2$

But since we have two semi circles here, we can simply multiply it by two and the formula becomes

$A = 2 * \frac{1}{2} \pi r^2\\A = \pi r^2$

But in the question, we have the diameter of the semi circle as the length of the rectangle.

$radius = \frac{diameter}{2} \\radius = \frac{64}{2} \\radius = 32m$

The radius of the semicircle is 32m

Area of the semicircle is

$A = \pi r^2\\A = 3.14 * 32^2\\A = 3215.36m^2$

The area of the field is

$area of field = 3215.36 + 5504\\area = 8719.36m^2$

The area of the field is equal to 8719.36m^2

Learn more on area of rectangle and semi circle here;

brainly.com/question/2906652

#SPJ1

7 0

2 years ago

HEY I RLLLLLLY NEED HELP! 50 POINTS AND BRAINLIEST IS YOU'RE RIGHT!!!!

BlackZzzverrR [31]

Answer:

g(f(x)) = 2x - 2

Step-by-step explanation:

<u>Given:</u>

f(x) = 2x + 1

and

g(x) = x - 3

<u>Find g(f(x)), substitute the value of f(x) into equation:</u>

g(f(x)) = g(2x + 1) = (2x + 1) - 3 = 2x - 2

7 0

2 years ago

Nicki was told to find three consecutive odd integers whose rum is 53. What is the right equation?

Lyrx [107]

The option D) x + x+2 + x+4 = 53 represents the exact equation of sum of three consecutive odd integers which is equal to 53.

<u>Step-by-step explanation:</u>

The sum of the three consecutive odd integers = 53

<u>To frame the equation :</u>

Let us consider any of the three consecutive odd integers.
Let us take 1,3,5 as the three consecutive odd integers.

Assume the first odd integer as 'x'. In this case, (x=1)

The second consecutive odd integer is 3.
The difference between 1 and 3 is 2.

Therefore, the second consecutive odd integer is x+2.

The third consecutive odd integer is 5.
The difference between 1 and 5 is 4.

Therefore, the third consecutive odd integer is x+4.

This means that, the sum of any three consecutive odd integers are given as x + x+2 + x+4.

Given that,

Sum of the three consecutive odd integers is 53.

The first odd integer + second odd integer + third odd integer = 53

x + x+2 + x+4 = 53.

The option D) x + x+2 + x+4 = 53 represents the exact equation of sum of three consecutive odd integers which is equal to 53.

6 0

3 years ago

FACTORISE 16x^2-y^2+4yz-4z^2​

FACTORISE 16x^2-y^2+4yz-4z^2