Answer:
You see the answer just character limit
Set up a ratio comparing the sample portion to the whole portion.
x= # of all dogs likely to have chip
Sample: 8 out of 50
Whole: x out of 2,300
8/50= x/2300
cross multiply
(50*x)= (8*2300)
50x= 18400
divide both sides by 50
x= 368
ANSWER: 368 dogs in Clarkson are likely to have a microchip.
Hope this helps! :)
A is the answer of not I’m sorry for that
2 + 1 = 3
3 - 3 = 0
Hope this helped :)
-- He must have at least one of each color in the case, so the first 3 of the 5 marbles in the case are blue-green-black.
Now the rest of the collection consists of
4 blue
4 green
2 black
and there's space for 2 more marbles in the case.
So the question really asks: "In how many ways can 2 marbles
be selected from 4 blue ones, 4 green ones, and 2 black ones ?"
-- Well, there are 10 marbles all together.
So the first one chosen can be any one of the 10,
and for each of those,
the second one can be any one of the remaining 9 .
Total number of ways to pick 2 out of the 10 = (10 x 9) = 90 ways.
-- BUT ... there are not nearly that many different combinations
to wind up with in the case.
The first of the two picks can be any one of the 3 colors,
and for each of those,
the second pick can also be any one of the 3 colors.
So there are actually only 9 distinguishable ways (ways that
you can tell apart) to pick the last two marbles.
