25.50 Bc I looked it up bc I’m smart
Answer:
241°
Step-by-step explanation:
You are given the triangle internal angle (N) at Naples = 46°, and the side opposite a = 765 km. You are given the side b = 515 km, and asked to find an angle related to the internal angle opposite (C).
By the law of sines, the internal angle (C) at Canton is ...
sin(C)/b = sin(N)/a
C = arcsin((b/a)sin(N)) = arcsin(515/765·sin(46°)) ≈ 28.964°
The bearing from Elgin to Canton will be 270° less this angle, so is about 241°.
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Comment on your answer
Apparently, you added 29° to 270°, rather than subtracting. Since the direction from Elgin to Canton is south of west, the bearing angle must be between 180° and 270°. Note that a line west from Elgin will be parallel to the line east from Canton, so you can take advantage of alternate interior angles being congruent where the Elgin-Canton line crosses those parallel east-west lines.
Answer:
Step-by-step explanation:
Surface area = 2(12 × 8) + 2(12 × 3) + 2(3 × 8) = 312 in²
-7 < x < 7
or
x > -7 , x < 7
The first equation
6x^2 -18x-24=0
-the graph opens up
6(x^2 -3x -4)=0
6(x^2 -3x +9/4-4-9/4)=0
6(x-3/2)-25x6/4=
6(x-3/2)-75/2
-Vertex is at (3/2, -75/2)
-Axis of symmetry is x=3/2
Second equation
3r^2 -16r -12=0
-the graph opens up
...
