Answer:
the exact length of the midsegment of trapezoid JKLM =
i.e 6.708 units on the graph
Step-by-step explanation:
From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.
Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:







Thus; the exact length of the midsegment of trapezoid JKLM =
i.e 6.708 units on the graph
Origin = (0,0)
To find the units of distance subtract the given pair from origin
(0,4) - (0,0) = 4
The probability that the monthly payment is more than $1000 will be found as follows;
The payment is normally distributed, thus the z-score will be given by:
Z-score=(x-Mean)/(SD)
Mean=$982
SD=$180
Thus;
Z-score=(1000-982)/180=0.1
The probability associated with a z-score of 0.1 is 0.5398
Thus the probability that the monthly payment is more than $1000 will be:
P(x<1000)=1-0.5398=0.4602=46.02%