If the radius of the wheel below is 4.2 inches. What is the area of the wheel? Round to the nearest tenth place value.
2 answers:
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The approximate difference in the ages of the two cars, which depreciate to 60% of their respective original values, is 1.7 years.
Depreciation is to decrease in the value of a product in a period of time. This can be given as,
Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.
Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is . Thus, by the above formula for the first car,
Take log both the sides as,
Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.
Thus, the depreciation price of the car is 0.6y. Let the number of year is . Thus, by the above formula for the second car,
Take log both the sides as,
The difference in the ages of the two cars is,
Thus, the approximate difference in the ages of the two cars, which depreciate to 60% of their respective original values, is 1.7 years.
Learn more about the depreciation here;
Answer:
3√3
Step-by-step explanation:
For the problem shown here, your answer 3√3 is correct.
When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:
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If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.
<u>Example</u>:
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It is easy to demonstrate that none of the offered choices for this problem has the same value as 9/√3.
9/√3 ≈ 5.196. Offered choices have values of about 4.798, 1.732, 6.681, 23.196 -- none even close.
Please discuss this question with your teacher.