The distance of it away from zero cannot be a negative distance, distance is always positive therefor the absolute value will always be positive.
Short answer: no, absolute value is always positive
I hope this helps :)
Answer:
10213.33
Step-by-step explanation:
use the formula to answer this question
principal=7,200
rate=0.06
compounded anually=1
time=6
Hope it helped..
Answer:
The answer is 192.
Step-by-step explanation:
Answer:
4x-3y+12=0 is required eqn
Step-by-step explanation:
Let, 3,8 be x1,y1
9,16 be x2,y2
Now,
Eqn of st.line is y-y1 = y2-y2/x2-x1 * (x-x1)
y-8 = 16-8/9-3 * (x-3)
y-8 = 4/3*(x-3)
3y-24 = 4x-12
4x-3y+12=0 is required eqn