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Artyom0805 [142]
1 year ago
14

I'm trying to evaluate and solve this quadratic function and I get so lost on word problems I will include a picture

Mathematics
1 answer:
SashulF [63]1 year ago
4 0

Given:

The Revenue function R(x):

R(x)\text{ = 550x}

The cost function C(x) :

C(x)=1240+2x^2

Solution

1. Profit is the difference between the revenue and the cost. Hence, the Profit function P(x) is:

\begin{gathered} P(x)\text{ = R(x) - C(x)} \\ =550x-(1240+2x^2) \\ =550x-1240-2x^2 \end{gathered}

2. The vertical intercept of P(x) can be obtained by substituting x =0 into P(x)

\begin{gathered} P(x)=550x-1240-2x^2 \\ P(0)\text{ = 0 -1240 -0} \\ P(0)\text{ = -1240} \end{gathered}

Ordered Pair : (0, -1240)

If the company sells no items, they would lose $ 1240

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Consider the first order differential equation
AURORKA [14]

Answer:

For y(-7) =6.4

        The  largest interval  is  between  

                                       -\infty \to -5

For   y(-2.5) = -0.5.

          The  largest interval  is  between  

                                        -5 \to 5

For  y(0) = 0

          The  largest interval  is  between  

                                        -5 \to 5

For y(4.5) = -2.1.

            The  largest interval  is  between  

                                        -5 \to 5

For y(14)= 1.7.

                          The  largest interval  is  between  

                                        9 \to \infty        

   

Step-by-step explanation:

From m the question we are told that

     The first order differential equation is   \frac{y' -  t}{ t^2 -25} =  \frac{e^t}{t-9}

Now the first step is to obtain the domain of the differential equation

Now to do that let consider the denominators

  Now generally

                           t^2 - 25 \ne  0                                           side calculation

                   =>     t\ne \pm5                                                      t^2 - 25 =  0

                                                                                          t = \pm 5

Also              t-9\ne 0                                                     t -9 = 0

        =>          t\ne 9                                                            t= 9    

This means that this  first order differential equation is discontinuous at

       t =  -5 ,  \   \  t =  5 \ \  t =  9

  This  \  is \  illustrated \  below    \  \\      ------------------\\\. \ \ \  | \ \ \   \ \ \   \ \ \ \  \ \ \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \ \ |\\. \  -5 \ \ \ \ \  \ \ \ \ \ \ \  5 \ \ \ \ \ \ \ \ \ \ \ \ \   9

So

For y(-7) =6.4

        The  largest interval  is  between  

                                       -\infty \to -5

For   y(-2.5) = -0.5.

          The  largest interval  is  between  

                                        -5 \to 5

For  y(0) = 0

          The  largest interval  is  between  

                                        -5 \to 5

For y(4.5) = -2.1.

            The  largest interval  is  between  

                                        -5 \to 5

For y(14)= 1.7.

                          The  largest interval  is  between  

                                        9 \to \infty        

   

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aleksley [76]

the answer is....

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3 0
4 years ago
Find the slope of the line going through the points (0,6) and (-3,9)
andre [41]

Answer:

The slope of the line is 5.

The point slope form of the line is y=5x+6.

Step-by-step explanation:

We can find the slope using this formula: \frac{y_{2} }{x_{2} } -\frac{y_{1} }{x_{1} }

\frac{6}{0} -\frac{9}{-3} =

\frac{6}{0} -(-\frac{9}{3} )=

\frac{6}{0} +\frac{9}{3} =

\frac{15}{3} =

5

The slope of the line is 5.

To find point slope form, we use the equation y=mx+b where m is the slope and b is the y-intercept.

The y-intercept of this slope is 6 and the slope is 5 so we get, y=5x+6

7 0
3 years ago
The measure of major arc TBU is_degrees.
Elina [12.6K]

Answer:

46°

Step-by-step explanation:

The alternate segment theorem states that for a circle, the angle between a chord and a tangent through the endpoint of one of the chord is equal to the angle in the alternate segment.

Therefore from the diagram attached, chord TU and the tangent UV form an angle (arc TBU). The alternate segment to arc TBU is ∠ TUV .

Therefore arc TBU = ∠ TUV. But arc TBU = 46°. Therefore:

∠ TUV = 46°

5 0
3 years ago
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