Answer:
D
Step-by-step explanation:
Just substitute your point (1,0) to each equation given.
I'll first substitute it into D
y=3(x-1)
0=3(1-1)
0=3(0)
0=0
The answer is D
Answer:
Hope it may help u
Step-by-step explanation:
The sum of two numbers is 44 and their difference is 14. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.
The sum of x and y is 44. In other words, x plus y equals 44 and can be written as equation A:
x + y = 44
The difference between x and y is 14. In other words, x minus y equals 14 and can be written as equation B:
x - y = 14
Now solve equation B for x to get the revised equation B:
x - y = 14
x = 14 + y
Then substitute x in equation A from the revised equation B and then solve for y:
x + y = 44
14 + y + y = 44
14 + 2y = 44
2y = 30
y = 15
Now we know y is 15. Which means that we can substitute y for 15 in equation A and solve for x:
x + y = 44
x + 15 = 44
X = 29
Summary: The sum of two numbers is 44 and their difference is 14. What are the two numbers? Answer: 29 and 15 as proven here:
Sum: 29 + 15 = 44
Difference: 29 - 15 = 14
(2/7)m - (1/7) = 3/14
2m/7 =(3/14) + (1/7)
2m/7 = (3/14) + 2(1/7)
here we are multiplying 2 with 1/7 to make the denominator same for addition.
2m/7 = (3/14) +(2/14)
2m/7 = (3 + 2)/14
2m/7 = 5/14
2m = (5 *7)/14
2m = 35/14
2m = 5/2
m = 5/4
m = 1.25
So the value of "m" is 1.25
<h3>The two possible values for x are x = 60 and x = -9</h3>
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Explanation:
Let's assume that x is the largest value of the list. If so then x = 60 because
range = max - min
range = x - 1
range = 60-1
range = 59
Effectively, you work backwards to go from a range of 59 to have x = 60 as the max.
So x = 60 is one possible value. We can't have x any larger or the range would be larger.
But we can have x be smaller. Specifically, it would be the min of the list. If negative x values are allowed, then x = -9 is the other possible x value
Here's why
range = max - min
range = 50 - x
range = 50 - (-9)
range = 50+9
range = 59
The answer is a
there's not a horizontal asymptote
y = 0 <span />
