4,153+2,988
-12 +12
4,141+3,000
3,000+4,000=7,000
7,000+141=7,141
Answer:
Step-by-step explanation:
Discussion
What you have presented is called a cyclic quadrilateral. A cyclic quadrilateral is a 4 sided figure whose angles (4 of them) all touch the circumference of a circle.
Here's what you want to know. Two angles that are opposite each other are supplementary (they add to 180 degrees)
Equation
x + 80 = 180 Subtract 80 from both sides.
Solution
x + 80 - 80 = 180 - 80 Combine
x = 100
Answer
x = 100
Point B on the ground is 5 cm from point E at the entrance to Ollie's house.
Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.
The complete question is as follows:
Ollie has installed security lights on the side of his house that is activated by a sensor. The sensor is located at point C directly above point D. The area covered by the sensor is shown by the shaded region enclosed by triangle ABC. The distance from A to B is 4.5 m, and the distance from B to C is 6m. Angle ACB is 15°.
The objective of this information is:
- To find angle CAB and;
- Find the distance Ollie is from the entrance to his house when he first activates the sensor.
The diagrammatic representation of the information given is shown in the image attached below.
Using cosine rule to determine angle CAB, we have:
Here:
∠CAB = Sin⁻¹ (0.3451)
∠CAB = 20.19⁰
From the diagram attached;
- assuming we have an imaginary position at the base of Ollie Standing point called point F when Ollie first activates the sensor;
Then, we can say:
∠CBD = ∠GBF
∠GBF = (CAB + ACB)
(because the exterior angles of a Δ is the sum of the two interior angles.
∠GBF = 15° + 20.19°
∠GBF = 35.19°
Using the trigonometric function for the tangent of an angle.
BF = 2.55 m
Finally, the distance of Ollie║FE║ from the entrance of his bouse is:
= 5 - 2.55 m
= 2.45 m
Therefore, we can conclude that Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.
Learn more about exterior angles here:
Answer:
Please see attachment
Step-by-step explanation:
Please see attachment
Answer:
length of the longest pencil that can fit must be less than 13cm
Step-by-step explanation:
To get the longest pencil that fit the case, we will use the pythagoras theorem;
diameter = 10cm
radius = 10/2
radius = 5cm
Height = 12cm
Get the length of the longest side
l² = r²+h²
l² = 5²+12²
l² = 25 + 144
l² = 169
l = √169
l = 13cm
Hence the length of the longest pencil that can fit must be less than 13cm